这个作业好吗？ [英] Is this assignment ok?
问题描述
char * pA [5];
char * pB [5];
pA = pB;
这不编译。
第二个想法，是吗？
（x）char * pA [5]意思是
（a）指向5个字符的指针或者
（b）指向一个角色的5个指针 ？
如果（x）==（b）那么（a）如何宣布？
任何帮助都将受到赞赏。< br>
Colin JN Breame写道：
char * pA [5];
char * pB [5];
pA = pB;
这不会编译。
不足为奇。
pA是一个数组的名称（一个5个指向char的数组）
pB是数组的名称（指向char的5个指针的数组）
pA和pB都不可更改，尽管它们的/ contents /是。
再想一想，
（x）char * pA [5]是什么意思
（a）指向5个字符的指针或者
（b）指向一个角色的5个指针 ？
（b）
如果（x）==（b）那么（a）如何宣布？
char（* pA）[5];
任何帮助都将不胜感激。
-
Lew Pitcher，IT顾问，应用程序架构
企业技术解决方案，道明银行金融集团
（意见表达这是我自己的，而不是我的雇主的）
在文章< bh ********** @ oravannahka.helsinki .fi>，
Joona I Palaste< pa ***** @ cc.helsinki.fi>写道：Colin JN Breame< c。********** @ durham.ac.uk>潦草地写下：（a）指向5个字符的指针或
如果（x）==（b）那么（a）如何宣布？
char（* pB）[5];
这是指向（和数组）五个字符指针的指针。
指向（数组）5个字符的指针将是：
char * p [5];
- Brett
>>第二个想法，（x）char * pA [5]意味着
等于
* pa0 * pa1 * pa2 * pa3 * pa4
（参见argv提示提示！）
（a）指向5个字符的指针或者
（b）指向一个角色的5个指针 ？
这意味着指向一个角色的5个指针。
对我来说，这是一个指向字符串的5个指针（'aka' ;字符数组"）
if（x）==（b）那么（a）如何声明？
char（* pB）[5];
因为IMO *在[]之前占优势（是吗？如果我不正确，请帮助）
我说它是'char *'的5 ptrs因此（* pb）[5]相当于* pb [5]
-
- Jan Engelhardt
char *pA[5];
char *pB[5];
pA = pB;
This doesnt compile.
On second thoughts, does
(x) char *pA[5] mean
(a) "A pointer to 5 characters" or
(b) "5 pointers to a character" ?
If (x) == (b) then how would (a) be declared?
Any help would be appreciated.
Colin JN Breame wrote:
char *pA[5];
char *pB[5];
pA = pB;
This doesnt compile.
Not surprisingly.
pA is the name of an array (an array of 5 pointers to char)
pB is the name of an array (an array of 5 pointers to char)
Neither pA nor pB is alterable, although their /contents/ are.
On second thoughts, does
(x) char *pA[5] mean
(a) "A pointer to 5 characters" or
(b) "5 pointers to a character" ?
(b)
If (x) == (b) then how would (a) be declared?
char (*pA)[5];
Any help would be appreciated.
--
Lew Pitcher, IT Consultant, Application Architecture
Enterprise Technology Solutions, TD Bank Financial Group
(Opinions expressed here are my own, not my employer''s)
In article <bh**********@oravannahka.helsinki.fi>,
Joona I Palaste <pa*****@cc.helsinki.fi> wrote:Colin JN Breame <c.**********@durham.ac.uk> scribbled the following:(a) "A pointer to 5 characters" or
If (x) == (b) then how would (a) be declared?
char (*pB)[5];
That''s a pointer to (and array of) five pointers to characters.
A pointer to (an array of) 5 characters would be:
char *p[5];
-- Brett
>> On second thoughts, does(x) char *pA[5] mean
is _roughly_ equivalent to
*pa0 *pa1 *pa2 *pa3 *pa4
(see argv hint hint!)
(a) "A pointer to 5 characters" or
(b) "5 pointers to a character" ?
It means 5 pointers to a character.
For me this is 5 pointers to a string (′aka "character array")
If (x) == (b) then how would (a) be declared?
char (*pB)[5];
Because IMO * takes precende before [] (does it? please help if I am incorrect)
I say it''s 5 ptrs to "char*" and thus (*pb)[5] is equivalent to *pb[5]
--
- Jan Engelhardt
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