如何将Byte数组转换为char数组？ [英] How to convert a Byte array to a char array?

问题描述

如何将字节数组（unsigned char managed）转换为

帐户？

帐户的

char数组（非托管）？

解决方案

Byte barray [] = new Byte [512];

__wchar_t * arr = new __wchar_t [barray-> Length];

for（int i = 0; i< barray-> Length; i ++）

arr [i] = barray [i];

删除arr;


-

问候，

Nish [VC ++ MVP]


Kueishiong Tu < KS **** @ seed.net.tw>在留言中写道

新闻：2d **************************** @ phx.gbl ... < blockquote class =post_quotes>如何将字节数组（unsigned char managed）转换为带有宽字符的
字符数组（非托管）？

-----原始消息-----
字节barray [] =新字节[512];
__wchar_t * arr = new __wchar_t [barray-> Length];
for（int i = 0; i< barray-> Length; i ++）
arr [i] = barray [i];
delete arr;

如何进一步转换为声明为char的数组

访问char数组已经考虑了广泛的特性。即，如果


char * cpp;

int n;

cpp = carray;


（cpp + n）将始终指向有效的宽字符（n任何
int）。

字节barray [] =新字节[512];


//字符这里是16位

char smallarray [512];

for（int i = 0; i< barray-> Length; i ++）

smallarray [i] = barray [i];


/ / Char这里是32位

Char carray [] =编码:: ASCII-> GetChars（barray）;

-

问候，

Nish [VC ++ MVP]


" Kueishiong Tu" < KS **** @ seed.net.tw>在留言中写道

news：2f **************************** @ phx.gbl ... < blockquote class =post_quotes>

-----原始消息-----
Byte barray [] = new Byte [512];
__wchar_t * arr = new __wchar_t [barray-> Length];
for（int i = 0; i< barray-> Length; i ++）
arr [i] = barray [i];
delete arr;

如何进一步转换为声明为char
carray []的数组？通过指针访问char数组
考虑了广泛的特性。即，如果

char * cpp;
int n;
cpp = carray;

（cpp + n）将始终指向有效的宽charater（n any
int）。

How do I convert a Byte array (unsigned char managed) to a
char array(unmanaged) with wide character taken into
account?

解决方案

Byte barray[] = new Byte[512];
__wchar_t* arr = new __wchar_t[barray->Length];
for(int i=0; i < barray->Length; i++)
arr[i] = barray[i];
delete arr;

--
Regards,
Nish [VC++ MVP]

"Kueishiong Tu" <ks****@seed.net.tw> wrote in message
news:2d****************************@phx.gbl...

How do I convert a Byte array (unsigned char managed) to a
char array(unmanaged) with wide character taken into
account?

-----Original Message-----
Byte barray[] = new Byte[512];
__wchar_t* arr = new __wchar_t[barray->Length];
for(int i=0; i < barray->Length; i++)
arr[i] = barray[i];
delete arr;

How do I further convert to a array declared as char
carray[]? The access of a char array through its pointer
has taken the wide character into account. i.e., if

char *cpp;
int n;
cpp = carray;

(cpp+n) will always point to a valid wide charater (n any
int).

Byte barray[] = new Byte[512];

//char here is 16 bits
char smallarray[512];
for(int i=0; i<barray->Length; i++)
smallarray[i] = barray[i];

//Char here is 32 bits
Char carray[] = Encoding::ASCII->GetChars(barray);
--
Regards,
Nish [VC++ MVP]

"Kueishiong Tu" <ks****@seed.net.tw> wrote in message
news:2f****************************@phx.gbl...

-----Original Message-----
Byte barray[] = new Byte[512];
__wchar_t* arr = new __wchar_t[barray->Length];
for(int i=0; i < barray->Length; i++)
arr[i] = barray[i];
delete arr;

How do I further convert to a array declared as char
carray[]? The access of a char array through its pointer
has taken the wide character into account. i.e., if

char *cpp;
int n;
cpp = carray;

(cpp+n) will always point to a valid wide charater (n any
int).

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