print $ str [英] print $str

问题描述

您好。我是非常新的PHP。你可以帮我这个：

这段代码打印字符串的一部分：image和image_id，但是gameandtoyname和pricetype NO。我做错了什么？任何帮助？


<？php

$ sql =" SELECT gameandtoyname，pricetype * FROM dollsimage，dolls where dollsimage.image_id = dolls.image_id" ;

$ sql =" SELECT * FROM dollsimage ORDER BY image_date DESC" ;;

$ result = mysql_query（$ sql，$ conn）;

if（mysql_num_rows（$ result）> 0）{

while（$ row = mysql_fetch_array（$ result，MYSQL_ASSOC））{

$ i ++;

$ str。= $ i。"。 " ;;


$ str。="< img border = \" 1 \"高度= \" 90\"宽度= \" 100\" SRC = \" imagedolls.php ACT =视图&安培; IID = QUOT; $行[" image_id"]。" " $行[" gameandtoyname"]。" " $行[" pricetype"]。" \">< / A> ;


}

打印$ str;

}

？>

Hi. I am very new with php. can you help me with this:
This code is printing part of the string: image and image_id, but gameandtoyname and pricetype NO. What i am doing wrong? any help?

<?php
$sql = "SELECT gameandtoyname,pricetype * FROM dollsimage, dolls where dollsimage.image_id=dolls.image_id";
$sql = "SELECT * FROM dollsimage ORDER BY image_date DESC";
$result = mysql_query ($sql, $conn);
if (mysql_num_rows($result)>0) {
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$i++;
$str .= $i.". ";

$str .="<img border=\"1\" height=\"90\" width=\"100\" src=\"imagedolls.php?act=view&iid=".$row["image_id"]." ".$row["gameandtoyname"]." ".$row["pricetype"]." \"></a> ";

}
print $str;
}
?>

推荐答案

sql =" SELECT gameandtoyname，pricetype * FROM dollsimage，dolls where dollsimage.image_id = dolls.image_id" ;;

sql = "SELECT gameandtoyname,pricetype * FROM dollsimage, dolls where dollsimage.image_id=dolls.image_id";

sql =" SELECT * FROM dollsimage ORDER BY image_date DESC" ;;

sql = "SELECT * FROM dollsimage ORDER BY image_date DESC";

result = mysql_query（

result = mysql_query (

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