printf warning：" format％08x expect format unsigned int ..." [英] printf warning: "format %08x expects format unsigned int ..."
问题描述
....但我在printf中有一个unsigned long值。
当我使用gcc 4.x编译时出现了这个警告。
... 。
unsigned long offset = 0;
....
好吧，简单方式将取而代之的是
printf（在偏移％08x处找到eof，偏移）;
做类似演员如
printf（"'eof found at offset％08x"，（unsigned int）offset）;
很好，但这应该适用于像0xFFFFFFFF这样的值，这是
afaik最后可能的长值。 unsigned int只转到0xFFFF。
因此，如果我在进行试错法之前想一想，我认为它更好
忽略警告并跳过类型转换。
因为只是逻辑，它不能用于（unsigned int）类型转换为
整个ulong范围0x00000000..0xFFFFFFFF。 br />
-Andreas
.... but I have an unsigned long value in the printf.
This warning came when I used gcc 4.x to compile.
....
unsigned long offset = 0;
....
Well OK, an "easy" way would be instead of
printf ("eof found at offset %08x", offset);
to do a type cast like
printf ("eof found at offset %08x", (unsigned int) offset);
Fine, but is this supposed to work for values like 0xFFFFFFFF, which is
afaik the last possible long value. Unsigned int only goes to 0xFFFF.
So if I think before going the trial-and-error way, I conclude it''s better
to ignore the warning and skip the type cast.
Because just by logic, it cannot work with an (unsigned int) typecast for
the whole ulong range 0x00000000..0xFFFFFFFF.
-Andreas
推荐答案
Andreas Eibach写道：
Andreas Eibach wrote:
....但我在printf中有一个unsigned long值。
当我使用gcc 4.x编译时出现了这个警告。
....
unsigned long offset = 0;
....
好吧，容易"方式将取而代之的是
printf（在偏移％08x处找到eof，偏移）;
进行类似
的类型转换
.... but I have an unsigned long value in the printf.
This warning came when I used gcc 4.x to compile.
....
unsigned long offset = 0;
....
Well OK, an "easy" way would be instead of
printf ("eof found at offset %08x", offset);
to do a type cast like
" cast"
"cast"
printf（" eof found at offset％08x"，（unsigned int）offset） ;
很好，但是这应该适用于像0xFFFFFFFF这样的值，这是最后一个可能的长值。
afaik。 unsigned int只转到0xFFFF。
printf ("eof found at offset %08x", (unsigned int) offset);
Fine, but is this supposed to work for values like 0xFFFFFFFF, which is
afaik the last possible long value. Unsigned int only goes to 0xFFFF.
" 08lx"应该做无条件的工作。
-
Ian Collins
"08lx" should do the job for unsigned long.
--
Ian Collins
Ian Collins< ; ia ****** @ hotmail.comwrites：
Ian Collins <ia******@hotmail.comwrites:
Andreas Eibach写道：
Andreas Eibach wrote:
[ ...]
[...]
>好吧，简单方式将是而不是
printf（在偏移％08x"找到eof，偏移）;
进行类型演员，如
>Well OK, an "easy" way would be instead of
printf ("eof found at offset %08x", offset);
to do a type cast like
" cast"
"cast"
[...]
我认为修正不清楚。 Ian的观点是，正确的
术语是强制转换，而不是强制转换。
-
Keith Thompson（The_Other_Keith） ks***@mib.org < http：//www.ghoti.net/~ kst>
诺基亚
"我们必须做点什么。这是事情。因此，我们必须这样做。
- Antony Jay和Jonathan Lynn，是部长
[...]
I think that correction was unclear. Ian''s point is that the correct
term is "cast", not "type cast".
--
Keith Thompson (The_Other_Keith) ks***@mib.org <http://www.ghoti.net/~kst>
Nokia
"We must do something. This is something. Therefore, we must do this."
-- Antony Jay and Jonathan Lynn, "Yes Minister"
Ian Collins < ia ****** @ hotmail.comwrote：
"Ian Collins" <ia******@hotmail.comwrote:
Andreas Eibach写道：
Andreas Eibach wrote:
....但是我在printf中有一个unsigned long值。
当我使用gcc 4.x编译时出现了这个警告。
....
unsigned long offset = 0;
....
好吧，简单方式将取而代之的是
printf（在偏移％08x处找到eof，偏移）;
进行类似
的类型转换
.... but I have an unsigned long value in the printf.
This warning came when I used gcc 4.x to compile.
....
unsigned long offset = 0;
....
Well OK, an "easy" way would be instead of
printf ("eof found at offset %08x", offset);
to do a type cast like
" cast"
"cast"
printf（" eof found at offset％08x"，（unsigned int）offset） ;
很好，但是这应该适用于像0xFFFFFFFF这样的值，这是最后一个可能的长值。
afaik。 unsigned int只转到0xFFFF。
printf ("eof found at offset %08x", (unsigned int) offset);
Fine, but is this supposed to work for values like 0xFFFFFFFF, which is
afaik the last possible long value. Unsigned int only goes to 0xFFFF.
" 08lx"应该做无条件的工作。
"08lx" should do the job for unsigned long.
谢谢，我又学到了一些东西。
我没有流血的想法，％x可以与小L一起_组合。
-Andreas
Thanks, I''ve learned something again.
I had no bleeding idea that the %x can be _combined_ with the small L.
-Andreas
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