帮助for，while和do-while循环 [英] Help in for, while and do-while loop
问题描述
我真的需要你的帮助。我需要一个程序，使用for，while和do-while循环... 3程序代码使用这3个循环得到下面的输出...请...我真的需要你的帮助。
输出：
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
1 2 3 4 5 6
1 2 3 4 5 6 7
1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 8 9 10
以及相反的
10 9 8 7 6 5 4 3 2 1
10 9 8 7 6 5 4 3 2
10 9 8 7 6 5 4 3
10 9 8 7 6 5 4
10 9 8 7 6 5
10 9 8 7 6
10 9 8 7
10 9 8
10 9
10
非常感谢非常感谢..非常感谢。
I really need your help everyone. i need a program that results the output below using for, while, and do-while loop..3 program codes using those 3 loops...please..i really need your help.
Output:
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
1 2 3 4 5 6
1 2 3 4 5 6 7
1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 8 9 10
and also the reverse
10 9 8 7 6 5 4 3 2 1
10 9 8 7 6 5 4 3 2
10 9 8 7 6 5 4 3
10 9 8 7 6 5 4
10 9 8 7 6 5
10 9 8 7 6
10 9 8 7
10 9 8
10 9
10
Great help is really appreciated..thank you very much.
推荐答案
最简单的接近方式问题是试图打印
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
1 2 3 4 5 6
1 2 3 4 5 6 7
1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 8 9 10
使用其中一个循环结构。
，例如使用while（）的伪代码中的算法类似于
the simplest way to approach the problem is to attempt to print
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
1 2 3 4 5 6
1 2 3 4 5 6 7
1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 8 9 10
using one of the loop constructs.
e.g. the algorithm in pseudo code using a while() would be something like
非常感谢您的快速回复先生..顺便说一下，我使用了for循环然后输出结果就是这样..
11212312345612345671234567812345678912345678910 :(
可以有人让我知道如何打破界限......？
这里是我的代码：
#include < iostream.h>
#include< conio.h>
int main（void ）
{
int i，j;
for（i = 1; I< = 10; i ++）
for（j = 1; j< = i; j ++）
cout<< j;
返回0;
}
Thank you very much for that quick reply sir..by the way, i used the for loop but then then the output turns out like this..
11212312345612345671234567812345678912345678910 :(
can somebody give me an idea how to break the line...?
here''s my code:
#include <iostream.h>
#include <conio.h>
int main (void)
{
int i, j;
for(i=1; i<=10; i++)
for(j=1; j<=i; j++)
cout << j;
return 0;
}
非常感谢你们快速回复先生..顺便说一句，我用了for循环然后输出结果就是这样..
11212312345612345671234567812345678912345678910 :(
有人能告诉我如何打破这条线......？
}
Thank you very much for that quick reply sir..by the way, i used the for loop but then then the output turns out like this..
11212312345612345671234567812345678912345678910 :(
can somebody give me an idea how to break the line...?
}
你忘了在外部循环的末尾打印换行符，例如
you forgot to print the newline at the end of the outer loop, e.g.
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