我需要逃避这段代码吗？ [英] Do I need to escape this code?
问题描述
嗨！
最近你们给了我一些好的建议后，我又回来了：o）
On在我的网站上，我想显示一个注销图标，下面有一些文字
，（注销），点击后会结束一个会话。
这是我用于图标的简单代码：
< a href ="<？php echo $ _SERVER [ '' PHP_SELF '']; ？>？action = log_out">
< img border =" 0" SRC ="图像/ logout.gif"宽度= QUOT; 74" height =" 74">< p
style =" text-align：center">
一切正常，当点击，会话结束，
用户返回我网站的主页。
现在很复杂，（好吧）我，无论如何），有点;我只想在用户实际登录时显示
''注销''图标。
所以，我一直在使用isset确定会话状态：
<？php if（isset（$ _ SESSION [''user'']））{？>
< ; a href ="<？php echo $ _SERVER [''PHP_SELF'']; ？>？action = log_out">
< img border =" 0" SRC ="图像/ greenround.PNG"宽度= QUOT; 74" height =" 74">< p
style =" text-align：center">
<？php}？>
现在 - 这只是部分有效;是的，图标仅在
用户登录时显示 - 这很酷。但是，当点击它时它不会做任何事情！
我想我应该在某个地方逃避一些代码，但我不能工作
out。这让我感到很沮丧!!
关于这个新手哪里出错的指导？
谢谢！
Rod。
Hi!
After you all gave me some good advice recently, I''m back for more :o)
On my web site, I want to display a ''log out'' icon with some text
underneath, ("Log out"), which, when clicked, will end a session.
This is the simple code I''m using for the icon:
<a href="<?php echo $_SERVER[''PHP_SELF'']; ?>?action=log_out">
<img border="0" src="images/logout.gif" width="74" height="74"><p
style="text-align: center">
This all works fine and, when clicked, the session is ended and the
user returns to my web site''s home page.
Now''s the complicated, (Well for me, anyway), bit; I only want to show
the ''log out'' icon when the user is actually logged in.
So, I''ve been using isset to determine the session state:
<?php if (isset($_SESSION[''user''])) {?>
<a href="<?php echo $_SERVER[''PHP_SELF'']; ?>?action=log_out">
<img border="0" src="images/greenround.PNG" width="74" height="74"><p
style="text-align: center">
<?php }?>
Now - this only partially works; yes, the icon is only shown when the
user is logged in - which is cool. However, when clicked it doesn''t do
anything!
I think I should be escaping some code somewhere but I can''t work it
out. And it''s frustrating me!!
Any guidance on where this newbie is going wrong?
Thanks!
Rod.
推荐答案
_SERVER [''PHP_SELF'']; ？>？action = log_out">
< img border =" 0" SRC ="图像/ logout.gif"宽度= QUOT; 74" height =" 74">< p
style =" text-align：center">
一切正常，当点击，会话结束，
用户返回我网站的主页。
现在很复杂，（好吧）我，无论如何），有点;我只想在用户实际登录时显示
''注销''图标。
所以，我一直在使用isset确定会话状态：
<？php if（isset（
_SERVER[''PHP_SELF'']; ?>?action=log_out">
<img border="0" src="images/logout.gif" width="74" height="74"><p
style="text-align: center">
This all works fine and, when clicked, the session is ended and the
user returns to my web site''s home page.
Now''s the complicated, (Well for me, anyway), bit; I only want to show
the ''log out'' icon when the user is actually logged in.
So, I''ve been using isset to determine the session state:
<?php if (isset(
_SESSION [''user'']））{？> ;
< a href ="<？php echo
_SESSION[''user''])) {?>
<a href="<?php echo
_SERVER [''PHP_SELF'']; ？>？action = log_out">
< img border =" 0" SRC ="图像/ greenround.PNG"宽度= QUOT; 74" height =" 74">< p
style =" text-align：center">
<？php}？>
现在 - 这只是部分有效;是的，图标仅在
用户登录时显示 - 这很酷。但是，当点击它时它不会做任何事情！
我想我应该在某个地方逃避一些代码，但我不能工作
out。这让我感到很沮丧!!
关于这个新手哪里出错的指导？
谢谢！
Rod。
_SERVER[''PHP_SELF'']; ?>?action=log_out">
<img border="0" src="images/greenround.PNG" width="74" height="74"><p
style="text-align: center">
<?php }?>
Now - this only partially works; yes, the icon is only shown when the
user is logged in - which is cool. However, when clicked it doesn''t do
anything!
I think I should be escaping some code somewhere but I can''t work it
out. And it''s frustrating me!!
Any guidance on where this newbie is going wrong?
Thanks!
Rod.
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