随机数问题 [英] Random Number Question

问题描述

有没有办法重复一组代码，直到某个if语句满足

。如果它然后退出循环，如果不重复代码？


说我想用PHP编写一个纸牌游戏应用程序，我想选择一个
$ b来自牌组的$ b卡$ card1 = rand（1,52）;得到我的第一张卡片。


我需要记录哪张卡已经发出，所以我有一个变量$ dealing

以字符串52开头零。我将$ / $ $ $ $ $ $字符串中的$ card1的位置更新为1。


因此，黑桃5中的$ deal =&000010000000000 ... ...


我想选择另一张卡，所以我使用$ card2 = rand（1,52）;然后需要

检查它是否已被处理。如果$ dealing中的位置为1，那么我需要重复随机数代码，直到它为0时我可以更新它

到1然后继续...


或者有更好的办法做这类事情吗？


一如既往的帮助，赞赏。 />

保罗。

Hi,

Is there a way to repeat a set of code until a certain if statement is
satisfied. If it is then to exit the loop and if not repeat the code?

Say I want to write a card game application in PHP and I want to chose a
card from the deck $card1 = rand(1,52); gets me my first card.

I need to record which card has been dealt so I have a variable $dealt which
starts out as a string of 52 zeros. I update the position of $card1 in the
$dealt string to "1".

So the 5 of Spades makes $dealt = "000010000000000 ..."

I want to choose another card so I use $card2 = rand(1,52); and then need to
check if it has already been dealt. If the position in $dealt is a 1 then I
need to repeat the random number code until it is a 0 when I can update it
to a 1 and move on ...

Or is there a better way of doing this sort of thing ??

Help, as always, appreciated.

Paul.

推荐答案

card1 = rand（1,52）;得到我的第一张卡片。


我需要记录哪张卡已被处理，所以我有一个变量

card1 = rand(1,52); gets me my first card.

I need to record which card has been dealt so I have a variable

处理了

以52个零的字符串开头。我在

dealt which
starts out as a string of 52 zeros. I update the position of

中更新了

card1的位置

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