操纵字符串 [英] manipulate string
问题描述
我听说字符串是不可变的，但是无论如何都不能用
操作字符串？
我有一个字符串看起来像这样： br />
a =''0123456789''
但我希望它看起来像这样：
a =''0 - 2 - 4 - 6 - 8 - ''
我希望每个数字之间都有空格，我希望淡出每个
的第二个数字。
我可以明确地说这很有趣阅读该字符串的部分，打印[3]
完美无缺，但我无法删除它，删除它或者什么都没有。
我我会很感激如何解决我的小问题。
非常感谢。
问候，汤姆
像这样：
导入字符串
a =''0123456789''
l = list（a）
b = string.join（l，'' - ''）
print b
@ -salutations
-
Michel Claveau
$ b $bmél： http://cerbermail.com/?6J1TthIa8B
Michel Claveau / Hamster写道：喜欢这个：
import string
a =''0123456789''
l = list（a）
b = string.join（l，'' - ''）
print b
显然，OP希望丢弃索引1,3,5,7等处的字符......所以，
假设Python版本为2.3 ，正确的解决方案似乎是：
a =''0123456789''
print'' - ''。join（a [:: 2]）
0 - 2 - 4 - 6 - 8
HTH
-
- Eric Brunel< eric dot brunel at pragmadev dot com> -
PragmaDev：实时软件开发工具 - http：//www.pragmadev .com
Oups！对不起，我看得太快......
I heard that strings are immutable, but isn''t there regardless a way to
manipulate a string?
I have a string that looks like this:
a = ''0123456789''
But I want it to look like this:
a = ''0 - 2 - 4 - 6 - 8 - ''
I want whitespace between every number and I want to fade out every
second number.
It is funny that I can explicitly read parts of that string, print a[3]
works perfectly, but I can''t remove it, delete it or what ever.
I would appreciate any hint on how to solve my little "problem".
Thanks a lot.
Regards, Tom
Like this :
import string
a=''0123456789''
l=list(a)
b=string.join(l,'' - '')
print b
@-salutations
--
Michel Claveau
mél : http://cerbermail.com/?6J1TthIa8B
Michel Claveau/Hamster wrote:Like this :
import string
a=''0123456789''
l=list(a)
b=string.join(l,'' - '')
print b
Apparently, the OP wants to discard characters at indexes 1, 3, 5, 7, etc... So,
assuming Python version is 2.3, the correct solution seems to be:
a=''0123456789''
print '' - ''.join(a[::2])
0 - 2 - 4 - 6 - 8
HTH
--
- Eric Brunel <eric dot brunel at pragmadev dot com> -
PragmaDev : Real Time Software Development Tools - http://www.pragmadev.com
Oups ! Sorry, i had read too fast...
这篇关于操纵字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
