inc unsigned（无论如何）超出限制。 [英] inc unsigned (whatever) beyond limit.

问题描述

当我做的时候.....

________________________________________________

unsigned int iTest; //让asume''int''= 32bit

iTest = 0xFFFFFFFF;

iTest ++;

________________________________________________


请问std说出现在会发生什么？

我可以安全地假设iTest现在为0或者它是CPU还是系统依赖的？

TIA，〜 .rhavin;）

解决方案

.. rhavin grobert写道：

当我这样做a .....

________________________________________________

unsigned int iTest; //让asume''int''= 32bit

iTest = 0xFFFFFFFF;

iTest ++;

________________________________________________


请问std说出现在会发生什么？

我可以安全地假设iTest现在为0或者是CPU还是sys依赖的？


TIA，〜.rhavin;）

第二个。


best，zeppe

On 21 Okt。，17：57，Zeppe< ze ... @ remove.all.this.long.comment.yahoo.it>

写道：

.rhavin grobert写道：

当我做的时候.....

________________________________________________

unsigned int iTest; * * //让asume''int''= 32bit

iTest = 0xFFFFFFFF;

iTest ++;

________________________________________________

会告诉std现在会发生什么吗？

我可以安全地假设iTest现在为0或是CPU还是sys依赖？

TIA，〜。rhavin;）

第二个。


最好，zeppe

CPU依赖？该死的，这是最糟糕的情况！

10月21日，11：57 * am，Zeppe

< ze ... @ remove.all.this.long.comment.yahoo.itwrot e：

.rhavin grobert写道：

当我做的时候.....

________________________________________________

unsigned int iTest; * * //让asume''int''= 32bit

iTest = 0xFFFFFFFF;

iTest ++;

________________________________________________

会告诉std现在会发生什么吗？

我可以安全地假设iTest现在为0或是CPU还是sys依赖？

TIA，〜。rhavin;）

第二个。


最好，zeppe

这是不正确的。假设unsigned int是32位，结果将是

总是为0.


REH

when i do a.....
________________________________________________
unsigned int iTest; // lets asume ''int'' = 32bit
iTest = 0xFFFFFFFF;
iTest++;
________________________________________________

does the std say something what shall happen now?
May i safely assume iTest is now 0 or is it CPU or sys-dependent?
TIA, ~.rhavin;)

解决方案

..rhavin grobert wrote:

when i do a.....
________________________________________________
unsigned int iTest; // lets asume ''int'' = 32bit
iTest = 0xFFFFFFFF;
iTest++;
________________________________________________

does the std say something what shall happen now?
May i safely assume iTest is now 0 or is it CPU or sys-dependent?
TIA, ~.rhavin;)

the second one.

best, zeppe

On 21 Okt., 17:57, Zeppe <[e-mail]>
wrote:

.rhavin grobert wrote:

when i do a.....
________________________________________________
unsigned int iTest; * *// lets asume ''int'' = 32bit
iTest = 0xFFFFFFFF;
iTest++;
________________________________________________

does the std say something what shall happen now?
May i safely assume iTest is now 0 or is it CPU or sys-dependent?

TIA, ~.rhavin;)

the second one.

best, zeppe

CPU-dependent? damn, that''s the worst case!

On Oct 21, 11:57*am, Zeppe
<[e-mail] e:

.rhavin grobert wrote:

when i do a.....
________________________________________________
unsigned int iTest; * *// lets asume ''int'' = 32bit
iTest = 0xFFFFFFFF;
iTest++;
________________________________________________

does the std say something what shall happen now?
May i safely assume iTest is now 0 or is it CPU or sys-dependent?

TIA, ~.rhavin;)

the second one.

best, zeppe

That is incorrect. Assuming unsigned int is 32-bits, result will
always be 0.

REH

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