string s ="" +（char）34; ！= Chr（34）还有！= \“等等 [英] string s=""+(char)34; != Chr(34) and also != \" etc.
问题描述
以下所有都没有正确进行VB.net双引号转换，因为
csharp中的所有以下内容转换为
\而不只是一个双引号：
我试过：
char myDoubleQuote =（char）34;
string myDoubleQuote ="" +（char）34;
string myDoubleQuote =" \"" ;;
myItems ="<？xml版本= QUOT; + myDoubleQuote +" 1.0" + myDoubleQuote +
"？>< users>" &安培; myXml& "< / users>"
我甚至尝试过：
myItems ="<？xml version =<！[CDATA [" ;]]> 1.0<！[CDATA ["]]>？><用户>" &
myXml& "< / users>"
它不能编译。
我需要字符串myItems才能正确处理在1.0的每一边创建一个
双引号：
myItems =<？xml version =" 1.0"？>< users + myXml +"< / users>
感谢您对此问题的帮助！
None of the following properly do the VB.net double quote conversion because
all of the following in csharp convert to
\" instead of just a double quote: "
I have tried:
char myDoubleQuote = (char)34;
string myDoubleQuote = "" + (char)34;
string myDoubleQuote = "\"";
myItems = "<?xml version=" + myDoubleQuote + "1.0" + myDoubleQuote +
"?><users>" & myXml & "</users>"
I even tried:
myItems = "<?xml version=<![CDATA["]]>1.0<![CDATA["]]>?><users>" &
myXml & "</users>"
it does not compile.
I need the string myItems to be able to properly handle the creation of one
double quote on each side of 1.0 :
myItems = <?xml version="1.0"?><users+ myXml + "</users>
Thank you for your help with this problem!
推荐答案
On Sun，2008年6月15日17:08:34 -0700，xzzy< mr ******** @ comcast.netwrote：
On Sun, 15 Jun 2008 17:08:34 -0700, xzzy <mr********@comcast.netwrote:
[...]
我需要字符串myItems才能正确处理创建
一个
每个双引号1.0的一面：
myItems =<？xml version =" 1.0"？>< users + myXml +"< / users>
[...]
I need the string myItems to be able to properly handle the creation of
one
double quote on each side of 1.0 :
myItems = <?xml version="1.0"?><users+ myXml + "</users>
假设前面的额外双引号< / users>是一个错字，
这应该有效：
string myItems ="<？xml version = \" 1.0 \"？> ;<用户>" + myXml +"< / users>"
不需要箍跳。
如果这不适合你，然后你需要发一个简单但完整的代码示例，这样我们就可以看到你的字符串中还有什么是
。
Pete
Assuming that the extra double-quote just before "</users>" is a typo,
this should work:
string myItems = "<?xml version=\"1.0\"?><users>" + myXml + "</users>"
No hoop-jumping required.
If that''s not working for you, then you will need to post a
concise-but-complete code sample, so that we can see what else is
happening to your string.
Pete
只有我的意见，Lisp和Double Quotes。 。 。他们俩都应该被带到巷子里，这样他们就可以在院子里死去，而不是死了几英寸。
彼得，谢谢你的时间换句话说，我需要字符串
myItems能够正确处理在1.0的每一边
上创建一个双引号：
最终结果必须是：
<？xml version =" 1.0"？blahblahblah< / users>
给出''myItems''是一个正在构建的字符串，如何生成：<？xml
version =" 1.0"？在csharp中传递给xml
对不起，我没有尽可能地解释，也许用不同的话来说
是对问题的更好理解。
" Peter Duniho" < Np ********* @nnowslpianmk.com在留言中写道
news：op *************** @ petes-computer.local ...
On Sun，2008年6月15日17:08:34 -0700，xzzy< mr ******** @ comcast.netwrote：
only my opinion, Lisp and Double Quotes . . . they both should be taken to
the alley so that instead of dying by inches, they can die by the yard.
Peter, thank you for your time, in different words, I need the string
myItems to be able to properly handle the creation of one double quote on
each side of 1.0 :
The end result must be:
<?xml version="1.0"?blahblahblah</users>
given that ''myItems'' is a string being built, how to generate: <?xml
version="1.0"? in csharp to pass to xml
Sorry I did not explain as well as I could, maybe in different words there
is a better understanding of the problem.
"Peter Duniho" <Np*********@nnowslpianmk.comwrote in message
news:op***************@petes-computer.local...
On Sun, 15 Jun 2008 17:08:34 -0700, xzzy <mr********@comcast.netwrote:
[...]
我需要字符串myItems才能正确处理创建
一个
双面引用1.0：
myItems =<？xml version =" 1.0"？>< users + myXml +"< / users>
[...]
I need the string myItems to be able to properly handle the creation of
one
double quote on each side of 1.0 :
myItems = <?xml version="1.0"?><users+ myXml + "</users>
假设前面的额外双引号< / users>是一个错字，
这应该有效：
string myItems ="<？xml version = \" 1.0 \"？> ;<用户>" + myXml +"< / users>"
不需要箍跳。
如果这不适合你，然后你需要发一个简单但完整的代码示例，这样我们就可以看到你的字符串中还有什么是
。
Pete
Assuming that the extra double-quote just before "</users>" is a typo,
this should work:
string myItems = "<?xml version=\"1.0\"?><users>" + myXml + "</users>"
No hoop-jumping required.
If that''s not working for you, then you will need to post a
concise-but-complete code sample, so that we can see what else is
happening to your string.
Pete
On Sun，2008年6月15日18:09:11 -0700，xzzy< mr ******** @ comcast.netwrote：
On Sun, 15 Jun 2008 18:09:11 -0700, xzzy <mr********@comcast.netwrote:
[...]
彼得，谢谢你的时间，换句话说，我需要字符串
myItems能够正确处理创建一个双重报价
每一边1.0：
[...]
Peter, thank you for your time, in different words, I need the string
myItems to be able to properly handle the creation of one double quote on
each side of 1.0 :
我发布的代码就是这样的。
The code I posted does that.
这篇关于string s ="" +（char）34; ！= Chr（34）还有！= \“等等的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
