有趣的位游戏 [英] Funny bit games
问题描述
您好。有一个任务是将一个int分成三个unsigned char'。
还有一个限制。给定int的最大大小是
10 ^ 9，只需17位就可以编码。那么，
问题是什么？如何将包含int的最多17个值位分成3个
无符号字符（8 + 8 + 1,6位）？问题是我不能使用
unsigned char指针，指向这样的int：
unsigned char * uchp;
unsigned int i = 1000000000;
uchp =& i;
for（int j = 0; j< sizeof（int）; ++ j）
cout<< * uchp;
指向int的每个字节...在汇编程序中可以执行什么
使用BYTE PTR，架构是Intel x86。但是如何使用C ++将int分成
三个无符号字符？
Isliguezze写道：
嗨。有一个任务是将一个int分成三个unsigned char'。
还有一个限制。给定int的最大大小是
10 ^ 9，只需17位就可以编码。那么，
问题是什么？如何将包含int的最多17个值位分成3个
无符号字符（8 + 8 + 1,6位）？
你是什么意思（8 + 8 + 1,6位）？如何将17位映射到三个字节的
位？
问题是我不能使用
unsigned char指针，指向这样的int：
unsigned char * uchp;
unsigned int i = 1000000000;
uchp =& i;
for（int j = 0; j< sizeof（int）; ++ j）
cout<< * uchp;
指向int的每个字节...在汇编程序中可以执行什么
使用BYTE PTR，架构是Intel x86。但是如何使用C ++将int拆分为
三个无符号字符？
请参阅按位运算符AND（&）和右移运算符（>>）。
应用蒙版，然后转移。
V
-
请在通过电子邮件回复时删除资金''A' />
我没有回复最热门的回复，请不要问
查看按位运算符AND（&）和右移运算符（>>）。
应用蒙版，然后移动。
我需要什么面膜？什么是面膜？它是如何构建的？
" Isliguezze" <是******** @ gmail.com写的消息
news：83 ********************** ************ @ k13g2000 hse.googlegroups.com ...
嗨。有一个任务是将一个int分成三个unsigned char'。
还有一个限制。给定int的最大大小是
10 ^ 9，只需17位就可以编码。那么，
问题是什么？如何将包含int的最多17个值位分成3个
无符号字符（8 + 8 + 1,6位）？问题是我不能使用
unsigned char指针，指向这样的int：
unsigned char * uchp;
unsigned int i = 1000000000;
uchp =& i;
for（int j = 0; j< sizeof（int）; ++ j）
cout<< * uchp;
指向int的每个字节...在汇编程序中可以执行什么
使用BYTE PTR，架构是Intel x86。但是如何使用C ++将int拆分为
三个无符号字符？
虽然这与你讨论的不一样，但使用工会打包/拆包8 b $ b位可以派上用场到时间：
-----
#include< iostream>
using namespace std;
void main（int argc，char * argv []）
{
typedef int XINT;
typedef char XBYTES [4];
union sigma
{
XINT xint;
XBYTES xbytes;
}测试;
test.xint =''ABCD'';
cout<< test.xbytes [0]<< endl;
cout<< test.xbytes [1]<< endl;
cout<< test.xbytes [2]<< endl;
cout<< test.xbytes [3]<<结束;
}
-----
IMO太少是有机会讨论工会的美德。虽然
我们的框架不超过8位（根据要求），但我们需要注意的是一些新技术。 （即''有趣的比赛''）
R.A. Nagy
http://www.Soft9000.com
Hi. There''s a task of splitting an int into three unsigned char''s.
There''s also one limitation. The maximum size of the given int is
10^9, what''s enough to code with as small as 17 bits. So, what is the
problem? How to split a maximum 17 value bits containing int into 3
unsigned chars(8+8+1, 6 bits)? The problem is that I can''t use
unsigned char pointer, to point on int like this:
unsigned char *uchp;
unsigned int i = 1000000000;
uchp = &i;
for (int j = 0; j < sizeof(int); ++j)
cout << *uchp;
to point on each byte of int... What can be performed in assembler
using BYTE PTR, architecture is Intel x86. But how to split int into
three unsigned chars using C++?
Isliguezze wrote:Hi. There''s a task of splitting an int into three unsigned char''s.
There''s also one limitation. The maximum size of the given int is
10^9, what''s enough to code with as small as 17 bits. So, what is the
problem? How to split a maximum 17 value bits containing int into 3
unsigned chars(8+8+1, 6 bits)?What do you mean by "(8+8+1, 6 bits)"? How do the 17 bits map into the
bits of the three bytes?
The problem is that I can''t use
unsigned char pointer, to point on int like this:
unsigned char *uchp;
unsigned int i = 1000000000;
uchp = &i;
for (int j = 0; j < sizeof(int); ++j)
cout << *uchp;
to point on each byte of int... What can be performed in assembler
using BYTE PTR, architecture is Intel x86. But how to split int into
three unsigned chars using C++?See the bitwise operator AND (&) and the right shift operator (>>).
Apply the mask, then shift.
V
--
Please remove capital ''A''s when replying by e-mail
I do not respond to top-posted replies, please don''t ask
See the bitwise operator AND (&) and the right shift operator (>>).Apply the mask, then shift.What do I need the mask for? What is mask? How is it constructed?
"Isliguezze" <is********@gmail.comwrote in message
news:83**********************************@k13g2000 hse.googlegroups.com...Hi. There''s a task of splitting an int into three unsigned char''s.
There''s also one limitation. The maximum size of the given int is
10^9, what''s enough to code with as small as 17 bits. So, what is the
problem? How to split a maximum 17 value bits containing int into 3
unsigned chars(8+8+1, 6 bits)? The problem is that I can''t use
unsigned char pointer, to point on int like this:
unsigned char *uchp;
unsigned int i = 1000000000;
uchp = &i;
for (int j = 0; j < sizeof(int); ++j)
cout << *uchp;
to point on each byte of int... What can be performed in assembler
using BYTE PTR, architecture is Intel x86. But how to split int into
three unsigned chars using C++?While this is not the same as what you are discussing, packing / unpacking 8
bits using a union can come in handy from time to time:
-----
#include <iostream>
using namespace std;
void main(int argc, char *argv[])
{
typedef int XINT;
typedef char XBYTES[4];
union sigma
{
XINT xint;
XBYTES xbytes;
} test;
test.xint = ''ABCD'';
cout << test.xbytes[0] << endl;
cout << test.xbytes[1] << endl;
cout << test.xbytes[2] << endl;
cout << test.xbytes[3] << endl;
}
-----
IMO far too few is the opportunity to discuss the virture of unions. While
we are not framing more than 8 bits (as requested), the technique is one for
a few new-of-us to be aware of. (i.e. ''funny bit games'' :)
R.A. Nagy
http://www.Soft9000.com
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