如何衡量代码效率？ [英] How to measure code-efficiency?
问题描述
时不时地找到两种解决问题的方法。我试着
找到一种方法来决定哪一个是最好的（至少在速度方面）但是我
我不知道如何测试它有多长拿一个程序来运行？
Every now and then and found two ways to resolve a problem. I try to
find a way to decide which one is best (at least speed-wise) but I
don''t know how do I test how long those it take a program to run?
推荐答案
Gaijinco写道：
Gaijinco wrote:
时不时地找到两种解决问题的方法。我试图找到一种方法来决定哪一个是最好的（至少在速度方面），但我不知道如何测试程序运行多长时间？
Every now and then and found two ways to resolve a problem. I try to
find a way to decide which one is best (at least speed-wise) but I
don''t know how do I test how long those it take a program to run?
我会给你一个普通的计时器（其中一个在
马拉松期间使用）：用一只手开始，而你用另一个按
one。
祝你好运...
告诉它如何去
I would you a regular timer (one of those that are used during
marathons): start in one hand, while you press enter with a different
one.
Good luck...
tell how it went
Gaijinco写道：
Gaijinco wrote:
时不时地找到两种解决问题的方法。我试图找到一种方法来决定哪一个是最好的（至少在速度方面），但我不知道如何测试程序运行多长时间？
Every now and then and found two ways to resolve a problem. I try to
find a way to decide which one is best (at least speed-wise) but I
don''t know how do I test how long those it take a program to run?
我执行这样的时间代码：
#include< ctime>
// ...
clock_t t0 = clock（）;
//插入要定时的代码 - -
double tElapsedSec = clock（） - t0;
tElapsedSec / = CLOCKS_PER_SEC;
// ...
DW
I time code execution like this:
#include <ctime>
// ...
clock_t t0 = clock();
// ---- insert code to be timed ----
double tElapsedSec = clock() - t0;
tElapsedSec /= CLOCKS_PER_SEC;
// ...
DW
> #include< ctime>
> #include <ctime>
// ...
clock_t t0 = clock（）;
// - - 插入要定时的代码----
double tElapsedSec = clock（） - t0;
tElapsedSec / = CLOCKS_PER_SEC;
// ...
// ...
clock_t t0 = clock();
// ---- insert code to be timed ----
double tElapsedSec = clock() - t0;
tElapsedSec /= CLOCKS_PER_SEC;
// ...
但是，如果经过的时间非常低，则会显示0.是否有任何方式
来衡量千分之一秒？
However, if the time elapsed is really low it shows 0. Is there any way
to measure thousandths of a second?
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