为什么这很糟糕 [英] why is this bad

问题描述

char * s =" " ;;


int main（）

{

strcpy（s，Hello World）;

}


这个程序很好地崩溃了。我认为s是一个指向字符串的指针

存储在可执行内存中，因此strcpy会覆盖程序的部分

，对吧？


我不会这样做，但是我发现了这个错误，我希望能够将这个错误解释给那个写它的人。

谢谢，


-

-Gernot

int main（int argc，char ** argv）{printf

（％silto％c％cf％cgl％ssic％ccom％c，ma，58，''g''，64，" ba"，46,10）; }


________________________________________

想找个好游戏？亲自动手吧！

GLBasic - 你可以这样做
www.GLBasic .com

char* s=" ";

int main()
{
strcpy(s, "Hello World");
}

This program crashes nicely. I think s is a pointer to a string that
is stored in the executable memory, so the strcpy will overwrite part
of the program, right?

I would not do this, but I found this error and I want to be able to
explain it to the one who wrote it.
Thank you,

--
-Gernot
int main(int argc, char** argv) {printf
("%silto%c%cf%cgl%ssic%ccom%c", "ma", 58, ''g'', 64, "ba", 46, 10);}

________________________________________
Looking for a good game? Do it yourself!
GLBasic - you can do
www.GLBasic.com

推荐答案

我想字符串文字存储在只读内存中。试试

char sz [256] =" " ;;

//等。

I guess the string literal is stored in read-only memory. Try
char sz[256] = " ";
//etc.

" Gernot Frisch" < [e-mail]>在消息中写道

news：31 ************* @ individual.net ...

"Gernot Frisch" <[e-mail]> wrote in message
news:31*************@individual.net...

char * s =" " ;;

int main（）
{
strcpy（s，Hello World）;
}

此程序很好地崩溃了。我认为s是指向存储在可执行内存中的字符串的指针，因此strcpy会覆盖部分程序，对吧？

我不会这样做，但我发现了这个错误，我希望能够把它解释给那个写它的人。
谢谢，

-
-Gernot
int main（int argc，char ** argv）{printf（"％silto％c％cf％cgl％ssic％ccom％c"，
" ma"，58，''g' '，64，" ba"，46,10）;}

________________________________________
寻找好游戏？亲自动手吧！
GLBasic - 你可以做
www.GLBasic.com

char* s=" ";

int main()
{
strcpy(s, "Hello World");
}

This program crashes nicely. I think s is a pointer to a string that is
stored in the executable memory, so the strcpy will overwrite part of the
program, right?

I would not do this, but I found this error and I want to be able to
explain it to the one who wrote it.
Thank you,

--
-Gernot
int main(int argc, char** argv) {printf ("%silto%c%cf%cgl%ssic%ccom%c",
"ma", 58, ''g'', 64, "ba", 46, 10);}

________________________________________
Looking for a good game? Do it yourself!
GLBasic - you can do
www.GLBasic.com

字符串文字实际上是const char *类型（即使你声明

你的只是char *） ，这可能就是崩溃的原因。
所以当声明字符串文字时总是使用类型const char *所以

编译器可以捕获这样的错误......如果你想修改字符串，声明

它为：

char foo [] = {" hello" };


/ WP

String literalts are really of type const char* (even though you declared
yours as just char*), that''s probably the reason for the crash.
So when declaring string literals always use type const char* so the
compiler can catch such errors...if you want to modify the string, declare
it as:
char foo[] = { "hello" };

/ WP

" William Payne" < ER ************* @ yahoo.com>在消息中写道

news：cp ********** @ news.island.liu.se ...

"William Payne" <er*************@yahoo.com> wrote in message
news:cp**********@news.island.liu.se...

Gernot弗里希" < [e-mail]>在消息中写道
新闻：31 ************* @ individual.net ...

"Gernot Frisch" <[e-mail]> wrote in message
news:31*************@individual.net...

char * s =" " ;;

int main（）
{
strcpy（s，Hello World）;
}

此程序很好地崩溃。

char* s=" ";

int main()
{
strcpy(s, "Hello World");
}

This program crashes nicely.

字符串文字实际上是const char *类型（即使你宣称你的只是char *），这可能是崩溃的原因。

String literalts are really of type const char* (even though you declared
yours as just char*), that''s probably the reason for the crash.

当然，有趣的是，为什么C ++类型机制

允许你初始化类型为< char *的对象>有一些东西

真的是一个< const char *> ？！？


IMO这是C ++类型机制的缺陷。


- Risto -

The interesting bit, of course, is why does C++ type mechanism
allow you to initialize an object of type <char *> with something
that really is a <const char *> ?!?

IMO that''s a flaw in C++ type mechanism.

- Risto -

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