这个警告意味着什么？ [英] What does this warning means?
问题描述
大家好，
我是C的新手，我正在研究一些简单的程序。我得到了
以下警告，我无法找到什么请问
让我知道导致此警告的原因。如果我忽略
这个警告怎么办？
inttoascii.c：38：警告：控制到达非空函数的结尾
Hi all,
I am new to C and I am working on some simple programs.I am getting
the following warning which I am not able to find what it is, please
let me know what is causing this warning.Also What happens if I ignore
this warning?
inttoascii.c:38: warning: control reaches end of non-void function
推荐答案
prashna< va ****** @ rediffmail。 COM>潦草地写道：
prashna <va******@rediffmail.com> scribbled the following:
大家好，
我是C的新手，我正在研究一些简单的程序。我得到了以下警告我无法找到它是什么，请
让我知道是什么导致了这个警告。如果我忽略了这个警告怎么办？
inttoascii.c：38：警告：控制到达非空函数的结尾
Hi all,
I am new to C and I am working on some simple programs.I am getting
the following warning which I am not able to find what it is, please
let me know what is causing this warning.Also What happens if I ignore
this warning? inttoascii.c:38: warning: control reaches end of non-void function
这意味着你已经定义了一个返回void
（这意味着它会返回任何可以赋值的类型），
并且你已经留下了一条路径让它完全执行而不会遇到
a" return"声明。这意味着，如果函数占用该路径，则返回值将无用。
-
/ - - Joona Palaste（pa*****@cc.helsinki.fi）--------------------------- \
| 飞翔的柠檬树中的金鸡王G ++ FR FW + M-＃108 D + ADA N +++ |
| http://www.helsinki.fi/~palaste W ++ B OP + |
\ -----------------------------------------芬兰的规则！ ------------ /
他说：''我不是猫王''。除了猫王之外还有谁能这么说？
- ALF
It means that you have defined a function returning other than void
(which means that it returns any type that you can assign values to),
and you''ve left a path for it to execute fully without ever encountering
a "return" statement. This means, if the function ever takes that path,
the returned value will be useless.
--
/-- Joona Palaste (pa*****@cc.helsinki.fi) ---------------------------\
| Kingpriest of "The Flying Lemon Tree" G++ FR FW+ M- #108 D+ ADA N+++|
| http://www.helsinki.fi/~palaste W++ B OP+ |
\----------------------------------------- Finland rules! ------------/
"He said: ''I''m not Elvis''. Who else but Elvis could have said that?"
- ALF
" prashna" < VA ****** @ rediffmail.com> schrieb im Newsbeitrag
新闻：d4 ************************** @ posting.google.c om ...
"prashna" <va******@rediffmail.com> schrieb im Newsbeitrag
news:d4**************************@posting.google.c om...
大家好，
我是C的新手，我正在研究一些简单的程序。我得到了以下警告，我无法找到它是什么，请
让我知道导致此警告的原因。如果我忽略了这个警告，会发生什么？
Redmont将被核攻击摧毁，也许:)
inttoascii.c：38：警告：控制到达无效功能的结束
Hi all,
I am new to C and I am working on some simple programs.I am getting
the following warning which I am not able to find what it is, please
let me know what is causing this warning.Also What happens if I ignore
this warning?
Redmont will be destroyed by a nuclear attack, perhaps :)
inttoascii.c:38: warning: control reaches end of non-void function
原因可能类似
int foo（int bar）
^^^^
{
/ *做一些酒吧* /
/ *然后你忘了退货，比如* /
返回0;
^^^^^^^^^^
}
罗伯特
The cause maybe something like
int foo(int bar)
^^^^
{
/*do something with bar*/
/*and then you forgot to return something, like*/
return 0;
^^^^^^^^^^
}
Robert
prashna写道：
prashna wrote:
大家好，
我是C的新手，我正在研究一些简单的程序。我得到了
以下警告，我无法找到它是什么，请
让我知道是什么原因引起了这个警告。
您应该发布您认为可能导致我的代码
在复制并尝试编译时会收到类似的警告。
我猜你有一个函数定义
应该在它前面有关键字void，但不是。
如果我忽略了这个警告会发生什么？
inttoascii.c：38：警告：控制到达非空函数的结尾
Hi all,
I am new to C and I am working on some simple programs.I am getting
the following warning which I am not able to find what it is, please
let me know what is causing this warning.
You should post code which you believe may cause me to
get a similar warning when I copy it and try to compile it.
I''m guessing that you have a function definition which
should have the keyword "void", in front of it, but doesn''t.
Also What happens if I ignore
this warning?
inttoascii.c:38: warning: control reaches end of non-void function
我建议你注意编译器警告，直到
你已经编程了大约十年，
然后重新考虑这个问题。
-
pete
I would advise you to pay attention to compiler warnings until
you have been programming for about ten years,
and then to reconsider the matter.
--
pete
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