需要相关文件路径的帮助 [英] Need help with relative file path
问题描述
嘿所有，
我正在写一个需要读取文件的c ++程序。我正在尝试阅读与可执行文件位于同一目录中的
a文件。
如果我在程序中执行程序，一切正常's
目录。我需要做的是读取该文件，无论在哪里
（cwd）我执行程序，而不是硬编码绝对的，因为
程序可能被移动或处于其他
电脑上的不同位置。
我该怎么办？
PS。如果它有帮助，我正在使用boost文件系统框架。
6月21日，8：11 * am，Thomas B？rlum< bor ... @ gmail.comwrote：
嘿所有，
我正在写一个需要的c ++程序阅读文件。我正在尝试阅读与可执行文件位于同一目录中的
a文件。
如果我在程序中执行程序，一切正常's
目录。我需要做的是读取该文件，无论在哪里
（cwd）我执行程序，而不是硬编码绝对的，因为
程序可能被移动或处于其他
电脑上的不同位置。
我该怎么办？
PS。如果它有帮助我正在使用boost文件系统框架。
大多数操作系统将为您提供用于执行程序的命令
argv [0]
这通常包括路径
int main（int argc，char * argv []）
{
std :: cout<< argv [0]<< \ n \ nn;
}
NB。它可能是绝对的或相对的。
Martin York写道：
大多数操作系统会给你用于执行程序的命令
argv [0]
这通常包括路径
实际上，argv [0]很简单就是你在命令行中用
编写的程序名称，没有任何附加内容。
< br>
2008-06-21 17:50:33 +0200，Martin York< Ma *************** @ gmail.comsaid：
< blockquote class =post_quotes>
6月21日，8：11 * am，Thomas B？rlum< bor ... @ gmail.comwrote：
>嘿所有，
我正在编写一个需要读取文件的c ++程序。我正在尝试阅读与可执行文件位于同一目录中的文件。
如果我在程序中执行程序，一切正常。
目录。我需要做的是读取该文件，无论我在哪里执行程序，而不用硬编码，因为程序可能被移动或处于其他地方的不同位置
电脑。
我该怎么办？
PS。如果它有帮助我正在使用boost文件系统框架。
大多数操作系统将为您提供用于执行程序的命令
argv [0]
这通常包括路径
int main（int argc，char * argv []）
{
std :: cout<< argv [0]<< \ n \ nn;
}
NB。它可能是绝对的或相对的。
感谢让我走上正轨。我已经完成了以下工作：
path program_path（string（argv [0]）+" /..& quot;）;
program_path = complete（program_path）;
string settings_file = program_path.string（）+" / setting.txt" ;;
效果很好。
Hey all,
I''m writing a c++ program that needs to read a file. I''m trying to read
a file that is in the same directory as the executable.
Everything works fine if I execute the program while in the program''s
directory. What I need to do is read that file regardless of where
(cwd) I execute the program from, without hardcoding the absolute since
the program might be moved or be in differant locations on other
computers.
What should I do?
PS. I''m using the boost filesystem framework if it helps.
On Jun 21, 8:11*am, Thomas B?rlum <bor...@gmail.comwrote:Hey all,
I''m writing a c++ program that needs to read a file. I''m trying to read
a file that is in the same directory as the executable.
Everything works fine if I execute the program while in the program''s
directory. What I need to do is read that file regardless of where
(cwd) I execute the program from, without hardcoding the absolute since
the program might be moved or be in differant locations on other
computers.
What should I do?
PS. I''m using the boost filesystem framework if it helps.Most OS''s will give you the command used to execute your program in
argv[0]
This will usually include the path
int main(int argc,char* argv[])
{
std::cout << argv[0] << "\n\n";
}
NB. It may be absolute or relative.
Martin York wrote:Most OS''s will give you the command used to execute your program in
argv[0]
This will usually include the pathActually it''s rather usual that argv[0] is simply what you wrote in
the command line as the program''s name, without any additions.
On 2008-06-21 17:50:33 +0200, Martin York <Ma***************@gmail.comsaid:
On Jun 21, 8:11*am, Thomas B?rlum <bor...@gmail.comwrote:>Hey all,
I''m writing a c++ program that needs to read a file. I''m trying to read
a file that is in the same directory as the executable.
Everything works fine if I execute the program while in the program''s
directory. What I need to do is read that file regardless of where
(cwd) I execute the program from, without hardcoding the absolute since
the program might be moved or be in differant locations on other
computers.
What should I do?
PS. I''m using the boost filesystem framework if it helps.
Most OS''s will give you the command used to execute your program in
argv[0]
This will usually include the path
int main(int argc,char* argv[])
{
std::cout << argv[0] << "\n\n";
}
NB. It may be absolute or relative.Thanks that got me on the right track. I''ve done the following:
path program_path(string(argv[0]) + "/..");
program_path = complete(program_path);
string settings_file = program_path.string() + "/settings.txt";
works great.
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