问题将值窗体弹出窗口传递到父窗口而不刷新父窗口 [英] Problem Passing value form popup window to parent window without refresh the parent
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问题描述
我要求出现我点击new.php的名称。 Window_open.php中的页面page..I也使用了一些Java脚本来完成这个但是我不能......
你能请求帮助...... !!!
I require to appear the Name which i click on the "new.php" page in the "Window_open.php" page..I use some Java Script also to accomplish this but I couldn''t..
Could you pleas Help ...!!!
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推荐答案
你能不能更好地解释一下你的要求......一步一步......这样吧更清楚你想要达到什么目标?
亲切的问候
could you please explain your requirement a bit better ... step by step ... so that it is more clear what you want to achieve?
kind regards
-Attach包含2页
01)。 window_open.php
02).new.php
Window_open.php是主页面和新的.php是Windows_open.php的弹出窗口
[请下载附件并运行Window_Open.php]
- 单击底部,然后在弹出窗口中显示名称列表..
要求: -
我需要显示名称当点击opoup窗口的名称时,它出现在主页面(window_open.php)的弹出窗口(new.php)中。
示例: - 运行window_open.php并单击按钮。 在弹出窗口的旁边有一个名称列表出现..点击名称..
通过关闭弹出窗口,名称应出现在主窗口中。 。
-Attach containing 2 pages
01).window_open.php
02).new.php
Window_open.php is the main page and new .php is the popup window of Windows_open.php
[Please Download the attachment and run the Window_Open.php]
-Click on the bottom and then appear the list of name in the popup window..
Requirment:-
I require to display the name which appear in the popup window("new.php") in the main page (window_open.php), when click on a name of the opoup window.
Example:- Run the window_open.php and click on the button. "in side the popup window there is a list of name appearing..Click on a name..
The name should be appear in the main window by closing the popup window...
线程合并...请不要双重发布您的问题并在一个主题中保留与特定问题相关的所有内容。
MOD
threads merged ... please don''t double post your questions and keep all things that are related to a specific problem in one thread.
MOD
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