深度克隆没有一些字段 [英] Deep clone without some fields

问题描述

让我有下一个javascript对象。现在我想克隆它，但没有一些字段。例如，我想要没有字段的克隆对象lastName和cars.age

输入

Let's I have next javascript object. Now I want clone it but without some fields. For example I want cloned object without field "lastName" and "cars.age"
Input

{
   "firstName":"Fred",
   "lastName":"McDonald",
      "cars":[
           {
              "type":"mersedes",
              "age":5
           },
           {
              "model":"bmw",
              "age":10
           }
       ]
}  

输出（克隆）

{
   "firstName":"Fred",
   "cars":[
       {
          "model":"mersedes"
       },
       {
          "model":"bmw"
       }
   ]
}   

我可以做类似的事情

var human = myJson   
var clone = $.extend(true, {}, human)  
delete clone.lastName  
_.each(clone.cars, function(car))  
{  
   delete car.age  
}  

您知道更简单的解决方案吗？

Do you know easier solution?

推荐答案

如果你不介意添加到对象原型，这是一个简单的解决方案。您可能需要修改它以供自己使用。

If you don't mind adding to object prototypes, this is an easy solution. You may want to modify it some for your own use.

Object.prototype.deepOmit = function(blackList) {
  if (!_.isArray(blackList)) { 
    throw new Error("deepOmit(): argument must be an Array");
  }

  var copy = _.omit(this, blackList);
  _.each(blackList, function(arg) {
    if (_.contains(arg, '.')) {
      var key  = _.first(arg.split('.'));
      var last = arg.split('.').slice(1);
      copy[key] = copy[key].deepOmit(last);
    }
  });
  return copy;
};

Array.prototype.deepOmit = function(blackList) {
  if (!_.isArray(blackList)) { 
    throw new Error("deepOmit(): argument must be an Array");
  }

  return _.map(this, function(item) {
    return item.deepOmit(blackList);
  });
};

然后当你有一个像这样的对象时：

Then when you have an object like:

var personThatOwnsCars = {
   "firstName":"Fred",
   "lastName":"McDonald",
      "cars":[
           {
              "type":"mersedes",
              "age":5
           },
           {
              "model":"bmw",
              "age":10
           }
       ]
};

你可以做这样的魔法。

personThatOwnsCars.deepOmit(["firstName", "cars.age"]);

甚至是这样的魔法！

[person1, person2].deepOmit(["firstName", "cars.age"]);

这篇关于深度克隆没有一些字段的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！