如何将变量从一个脚本传递到另一个脚本 [英] how do I pass a variable from one script to another

问题描述

这是一个我无法正常工作的脚本。
它的目的是检查复选框是否被选中，然后调用第二个响应的
例程，这取决于我最初调用脚本时所显示的selectedindex（sindex）的内容

Here is a script I can't get to work correctly. It's purpose is to check whether a check box is checked and then to call a second routine that responds, dependent on what the selectedindex (sindex) was shown to be when I originally called the script

<script type="text/javascript">
function checkB(ctrl,sindex) {  //get the state of the check box 
var sindex = {
    0: 0,
    1: 1,
    2: 2,
    3: 3
 };


if (ctrl.checked == true) { 
return function( which ) {
replaceContentmainobjectOn(sindex [which]);
} else {    
if (ctrl.checked == false) { 
replaceContentmainobjectOff();
}   
} 
}
</script>

这是第二个叫做的脚本

var replaceContentmainobjectOn =(function() {
var info = {
    0: 2,
    1: 1,
    2: 2,
    3: 3
 };

    return function( which ) {
    document.getElementById('ecwid-productoption-8840317-mainobject').selectedIndex = ( info[ which ] ) ;
};

}())

这就是我所说的第一个例行程序

This is what I'm calling the first routine with

onclick="checkB(this,sindex);

推荐答案

两个人< script> 块共享相同的执行范围，全局范围。您在一个< script> 中的全局范围内创建的所有变量都可以在另一个中访问。

Two individual <script> blocks share the same execution scope, the global scope. All variables you create in the global scope inside one <script> are accessible in the other.

<script>
    var a = 5;
</script>

<script>
    alert( a );
</script>

同样适用于函数。

<script>
    var b = function( c ){ return c; }
</script>

<script>
    alert( b(12) );
</script>

你可以排除，你的问题似乎存在于第一个脚本中，这不是语法上的有效。

That you can rule-out, your problem seems to lay in the first script, which is not syntactically valid.

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