安卓嫌库订阅（不显示inbond或outbond通知） [英] Android smack library subscription(not showing inbond or outbond notifications)
问题描述
我的工作中，我使用咂嘴库即时通讯一切正常，但巨大的问题是在订阅的机器人聊天应用程序。
I am working on an android chat application in which i am using smack library for instant messaging everything is working fine but the huge problem is in subscription.
如何发送订阅通知给其他用户。
How to send subscription notification to another user.
这是我的code发送订阅请求：
public void run() {
/*runOnUiThread(new Runnable() {
public void run() {*/
Roster roster = XMPPSmackConnection.getInstance().connection.getRoster();
roster.setSubscriptionMode(Roster.SubscriptionMode.manual);
try {
if(!_userName.contains("@"))
_userName=_userName+"@www.naijapings.net";
/*Presence presence = (Presence) packet;
Presence presence_request = new Presence(Presence.Type.subscribed);
presence_request.setTo(presence.getFrom());
presence_request.setType(Presence.Type.subscribed);
presence_request.setFrom("current_logged_in_user");
XMPPSmackConnection.getInstance().connection.sendPacket(presence_request);
roster.createEntry(presence.getFrom(), null, null);*/
/*Presence response = new Presence(Presence.Type.subscribe);
response.setTo(_userName);
XMPPSmackConnection.getInstance().connection.sendPacket(response);*/
//PROCESS TWO WAY COMMUNICATION
Presence response1 = new Presence(Presence.Type.subscribe);
response1.setTo(_userName);
XMPPSmackConnection.getInstance().connection.sendPacket(response1);
//////////////////////////////////////////////////////
//roster.createEntry(_userName, null, null);
/*roster.createEntry(_userName, _nickName, Friends);*/
//roster.createEntry(_tempUserName, null, null);
//roster.createEntry(_userName, _nickName, my_friends[]);
//addBuddy(_userName, _nickName, Friends);
} catch (Exception e) {
_progDailog.dismiss();
e.printStackTrace();
}
_progDailog.dismiss();
successAlert("Buddy requested successfully");
/*}
});*/
以上code只能建立名册进入其他用户的阵容名单，但没有表现出认购通知。
The above code only create roster entry to other user's roster list but not showing subscription notification.
下面是code接受预订请求：
runOnUiThread(new Runnable() {
public void run() {
try {
Roster roster = XMPPSmackConnection.getInstance().connection.getRoster();
///roster.setSubscriptionMode(Roster.SubscriptionMode.manual);
//Presence presence = roster.getPresence(_buddyUserName);
roster.setSubscriptionMode(Roster.SubscriptionMode.manual);
//Presence subscribed = new Presence(Presence.Type.subscribed);
Presence response = new Presence(Presence.Type.subscribed);
response.setTo(_buddyUserName);
XMPPSmackConnection.getInstance().connection.sendPacket(response);
/*response = new Presence(Presence.Type.subscribed);
response.setTo(_buddyUserName);
XMPPSmackConnection.getInstance().connection.sendPacket(response);*/
roster.createEntry(_buddyUserName, _nickNameEditText.getText().toString(), Friends);
} catch (Exception e) {
e.printStackTrace();
}
}
});
请建议确切的情况。
推荐答案
好了，我辛苦劳碌在这几天，最后得到的东西的工作。我已经实现了它与手动订阅模式（即用户需要接受其他用户的请求，以手动）。
Okay, I toiled hard at this for a couple of days and finally got things working. I have implemented it with a manual subscription mode (ie. user needs to accept another user's request manually).
服务器保留推订阅请求给用户（在重新登录），如果用户未发送订阅或退订回来。那么，你能做的就是在本地保存收到的认购请求在列表中，并显示为好友请求列表手工接受/拒绝。如果您的应用程序被重新启动（并因此重新连接到服务器），服务器将再次推订阅请求。
The server keeps pushing subscribe request to the user (upon re-login) if the user hasn't sent a subscribed or unsubscribed back. So what you can do is save the incoming subscribe requests locally in a list and display that as a "friend request list" for manual accept/reject. If your application gets restarted (and hence re-connects to server), the server will push subscribe requests again.
这是如何工作的：
- 在用户1发送订阅presence到用户2。
- 进入名册就会自动在用户1的花名册创建（而不是在用户2的名册）。
- 用户2接收来自用户1订阅的请求。
- 在用户2发回订阅presence到用户2（用户2>用户1认购完成）。
- 在用户2检查，如果用户1在用户2的花名册。用户1是不是在用户2的花名册。用户2发回一个认购presence为user1。
- 进入名册就会自动在用户2的花名册创建。
- 在用户1接收订阅presence从用户2。
-
用户1检查，如果用户2是在用户1的花名册。用户2在用户1的花名册。用户1发回一个订阅presence到用户2（用户2>用户1认购完成）。
- User1 sends subscribe presence to User2.
- Roster entry gets automatically created in User1's roster (but not in User2's roster).
- User2 receives subscribe request from User1.
- User2 sends back a subscribed presence to User2 (User2 > User1 subscription complete).
- User2 checks if User1 is in User2's roster. User1 is not in User2's roster. User2 sends back a subscribe presence to User1.
- Roster entry gets automatically created in User2's roster.
- User1 receives subscribe presence from User2.
User1 checks if User2 is in User1's roster. User2 is in User1's roster. User1 sends back a subscribed presence to User2 (User2 > User1 subscription complete).
final Presence newPresence = (Presence) packet;
final Presence.Type presenceType = newPresence.getType();
final String fromId = newPresence.getFrom();
final RosterEntry newEntry = getRoster().getEntry(fromId);
if (presenceType == Presence.Type.subscribe)
{
//from new user
if (newEntry == null)
{
//save request locally for later accept/reject
//later accept will send back a subscribe & subscribed presence to user with fromId
//or accept immediately by sending back subscribe and unsubscribed right now
}
//from a user that previously accepted your request
else
{
//send back subscribed presence to user with fromId
}
}
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