winmain中的命令行选项与__argv [英] command line options in winmain with __argv

问题描述

我想将winmain命令行上的内容与if语句进行比较。我收到一个beginers错误，但我没有一个例子可以用来修复它..无法转换为''const int''to''char *''在这一行if（__argv [1] =''file''）{};

我很遗憾这个错误，任何帮助都会被破坏

I want to compare what I get on the command line in winmain with an if statement.. I am getting a beginers error but I don''t have an example to use to fix it.. cannot convert from ''const int'' to ''char *'' in this line if (__argv[1] = ''file''){};
I am very lost with this error and any help would be apreaceated

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推荐答案

WinMain（）不是main（）。


Windows程序和论证中没有命令行必须使用 GetCommandLine（）<获取命令行中的nts / a>。


所有argc argv内容仅适用于本地语言控制台应用程序。

WinMain() is not main().

There is no command line in a Windows program and the arguments on the command line have to be fetched using GetCommandLine().

All that argc argv stuff is for native language console applications only.

它似乎编译正常，其中一个if我的工作就是当我寻找一个字符串而不是它抱怨的字符时..是否有一个例子，在另一个地方，我比较我得到的命令???我看到了但不明白如何使用它（没有好例子）

It seems to compile fine and one of the if''s is working it is when I look for a string instead of a charecter it complains.. is there an example of the other somewhere where I compare what I get with your command??? I saw that but didn''t understand how to use it (no good examples)

您可能需要发布修改后的代码。


GetCommandLine（）返回一个LPTSTR，如果您使用的是ASCII，则为char *;如果您使用的是Unicode，则为wchar_t *。


已为Unicode重写了各种C函数。如果您的peoject设置为ASCII，则需要ANSI C版本，而对于Unicode，则需要ANSI C宽字符版本。您可以使用TCHAR映射在这两者之间切换（请阅读此内容）。


函数映射是 http://msdn2.microsoft.com/en-us/library/ms860358.aspx 。

You may need to post your revised code.

GetCommandLine() returns an LPTSTR, which is a char* if you are using ASCII and a wchar_t* if you are using Unicode.

Various C functions have been rewritten for Unicode. When you have your peoject set for ASCII you want the ANSI C version and for Unicode you want the ANSI C wide character version. You switch between these two by using the TCHAR mappings (Please read up on this).

The function mappings are http://msdn2.microsoft.com/en-us/library/ms860358.aspx.

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