创建rss xml [英] create rss xml
问题描述
我正在创建xml提要，因为在网络数据提取后我的数据库中有数据准备好了b $ b。但是，这行有错误：
< xml version =" 1.0" encoding =" ISO-8859-1">
我无法解决这个问题。
< html>
< head>
< title> MMU RSS FEED< / title>
< / head>
< ; body>
header（" Content-type：application / xml"）;
< xml version =" 1.0" encoding =" ISO-8859-1"
< rss version =" 2.0">
< channel>
< title> MMU RSS FEED今天：<？php echo date（" D，dMY H：i：s"）？>< /
title>
< link> http：//bulletin.mmu.edu.my/< / link>
< description> MMU RSS FEED< / description>
< ttl> 60< ttl>
<？php
//连接到数据库
$ db = mysql_connect（" localhost"，" root"，""）或die（mysql_error（））;
mysql_select_db（" bulletin"，$ db ）或死（mysql_error（））;
$ day = date（" Yn-j"）;
//选择查询
$ sql =" SELECT * FROM`bul_data` WHERE`DATE` LIKE''{$ day}％''ORDER by
`DEPARTMENT`";
echo" sql ="。$ sql;
$ res = mysql_query（$ sql）或die（mysql_error（））;
if（mysql_ num_rows（$ res）> 0）
{
while（$ row = mysql_fetch_assoc（$ res））
{
$ date = $ row [''DATE''];
$ title = $ row [''TITLE''];
$ department = $ row [''DEPARTMENT''];
$ link = $ row [''LINK''];
//输出到浏览器
echo"< item>" ;;
echo"< title> $ title< / title>" ;;
echo"< category> $ department< / category>" ;;
echo"< link>< a href = \" $ link \" ;> $ link< / a>< / link>" ;;
echo"< / item>" ;;
}
echo"< / table>" ;;
}
？>
< / channel>
< / rss>
< / body>
< / html>
I''m currently working on creating the xml feed since I had data ready
in my database after web data extraction. However, it has errors for
this line:
<xml version="1.0" encoding="ISO-8859-1">
I was unable to solve this.
<html>
<head>
<title>MMU RSS FEED</title>
</head>
<body>
header("Content-type: application/xml");
<xml version="1.0" encoding="ISO-8859-1">
<rss version ="2.0">
<channel>
<title>MMU RSS FEED Today: <?php echo date("D, d-M-Y H:i:s")?></
title>
<link>http://bulletin.mmu.edu.my/</link>
<description>MMU RSS FEED</description>
<ttl>60<ttl>
<?php
//connect to database
$db = mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("bulletin", $db) or die(mysql_error());
$day = date("Y-n-j");
//select queries
$sql = "SELECT * FROM `bul_data` WHERE `DATE` LIKE ''{$day}%'' ORDER by
`DEPARTMENT`";
echo "sql=".$sql;
$res = mysql_query($sql) or die(mysql_error());
if(mysql_num_rows($res)>0)
{
while($row=mysql_fetch_assoc($res))
{
$date = $row[''DATE''];
$title = $row[''TITLE''];
$department = $row[''DEPARTMENT''];
$link = $row[''LINK''];
//output to browser
echo "<item>";
echo "<title>$title</title>";
echo "<category>$department</category>";
echo "<link><a href=\"$link\">$link</a></link>";
echo "</item>";
}
echo "</table>";
}
?>
</channel>
</rss>
</body>
</html>
推荐答案
db = mysql_connect（" localhost"，" roo t"，""）或die（mysql_error（））;
mysql_select_db（" bulletin"，
db = mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("bulletin",
db）或die（mysql_error（） ）;
db) or die(mysql_error());
day = date（" Yn-j"）;
//选择查询
day = date("Y-n-j");
//select queries
这篇关于创建rss xml的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
