列表：将Double转换为Single [英] Lists: Converting Double to Single
问题描述
我从一个从数据库表中检索的元组列表开始。这些
元组被提取并放入单独的列表中。所以我列出了
看起来像这样：[1,2,3,4,5]。当我连接列表时，我最终会得到一个
列表，如下所示：[[1,2,3,4,5]。 [6,7,8,9。10]]。
然后，我平均列值，所以我最终得到一个列表，但是
两个括号每一端，例如[[3.5,4.5,5.5,6.5,7.5]]。
不幸的是，当我尝试在NumPy函数中使用最后一个列表时，我'' m
告诉它无法播放到正确的形状。那么，我想要做什么
从每一端剥去额外的托架，只留下[3.5,4.5,5.5,6.5，
7.5]。
我该怎么办？
Rich
rs******@nospam.appl-ecosys.com 写道：
< blockquote class =post_quotes>
所以我的列表看起来像这样：[1,2,3,4,5]。当我将
连接列表时，我最终会得到一个列表，看起来像是这样的：[[1,2,3,4,5]。 [6,7,8,9。10]]。
真的吗？
>> [1,2,3,4,5] + [6 ，7,8,9,10]
[1,2,3,4,5,6,7,8， 9,10]
然后，我平均列值，所以我最终得到一个列表，但
每个都有两个括号结束，例如，[[3.5,4.5,5.5,6.5，
7.5]]。
不幸的是，当我尝试使用最后一个列表时一个NumPy函数，
我被告知它无法播放到正确的形状。所以，我想要做的就是从每一端剥去额外的托架，只留下
[3.5,4.5,5.5,6.5,7.5]。
l = l [0]
rs ****** @ nospam.appl-ecosys.com 写道：
我最终得到一个列表，但每端有两个括号，例如，
，[[3.5,4.5,5.5,6.5,7.5]]。
不幸的是，当我尝试在NumPy
函数中使用最后一个列表时，我告诉它不能广播到正确的形状。所以，我想要做的就是从每一端剥去额外的托叶，只留下
[3.5,4.5,5.5,6.5,7.5]。
我该怎么办呢？
轻松:)
我会举例告诉你：
>> ham = [[1,2,3]，[4,5,6]]
ham
[[1,2,3]，[4,5,6]]
>> ham [0]
[1,2,3]
>> ham。删除（[4,5,6]）
ham [0]
[1,2,3]
>> ham
[[1,2,3]]
>>>
HTH& Regards，
Bj？
-
BOFH借口＃453：
2007-02-27，Leif K-Brooks< eu ***** @ ecritters.bizwrote：
Lief，Bjoern：
l = l [0]
当然！如果我在一夜之间让它在我的脑海里工作，我几乎可以肯定地看到了这个。
感谢你们的耐心反应，
Rich
I start with a list of tuples retrieved from a database table. These
tuples are extracted and put into individual lists. So I have lists that
look like this: [1, 2, 3, 4, 5]. When I concatenate lists, I end up with a
list of lists that looks like this: [[1, 2, 3. 4, 5]. [6, 7. 8, 9. 10]].
Then, I average the column values so I end up with a single list, but with
two brackets on each end, for example, [[3.5, 4.5, 5.5, 6.5, 7.5]].
Unfortunately, when I try to use that last list in a NumPy function, I''m
told that it cannot be broadcast to the correct shape. So, what I want to do
is strip the extra brackes from each end to leave just [3.5, 4.5, 5.5, 6.5,
7.5].
How do I do this, please?
Rich
rs******@nospam.appl-ecosys.com wrote:So I have lists that look like this: [1, 2, 3, 4, 5]. When I
concatenate lists, I end up with a list of lists that looks like
this: [[1, 2, 3. 4, 5]. [6, 7. 8, 9. 10]].Really?
>>[1, 2, 3, 4, 5] + [6, 7, 8, 9, 10]
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
Then, I average the column values so I end up with a single list, but
with two brackets on each end, for example, [[3.5, 4.5, 5.5, 6.5,
7.5]].
Unfortunately, when I try to use that last list in a NumPy function,
I''m told that it cannot be broadcast to the correct shape. So, what I
want to do is strip the extra brackes from each end to leave just
[3.5, 4.5, 5.5, 6.5, 7.5].l = l[0]
rs******@nospam.appl-ecosys.com wrote:
I end up with a single list, but with two brackets on each end,
for example, [[3.5, 4.5, 5.5, 6.5, 7.5]].
Unfortunately, when I try to use that last list in a NumPy
function, I''m
told that it cannot be broadcast to the correct shape. So, what I
want to do is strip the extra brackes from each end to leave just
[3.5, 4.5, 5.5, 6.5, 7.5].
How do I do this, please?Easy :)
I''ll show you by example:
>>ham = [[1,2,3],[4,5,6]]
ham
[[1, 2, 3], [4, 5, 6]]
>>ham[0]
[1, 2, 3]
>>ham.remove([4,5,6])
ham[0]
[1, 2, 3]
>>ham
[[1, 2, 3]]
>>>
HTH&Regards,
Bj?rn
--
BOFH excuse #453:
Spider infestation in warm case parts
On 2007-02-27, Leif K-Brooks <eu*****@ecritters.bizwrote:
Lief, Bjoern:
l = l[0]Of course! If I had let it work in my mind overnight I would almost
certainly have seen this.
Thank you both for your patient responses,
Rich
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