枚举！ [英] enum !
问题描述
我有一个代码，其中我有一个枚举类似
enum ADDR
{
one = 0;
two = 1;
three = 2;
};
稍后在代码中，我有一个返回ADDR类型的函数，
返回一个指向正确值的整数但是我要打印
out名称一，二或三。
我怎么能这样做，我的例子有很多案例，所以不想使用
开关语句。
谢谢，
Kapil
"卡皮尔科斯拉 < KH ********* @ yahoo.com>在留言中写道
news：91 ************************** @ posting.google.c om ...
我有一个代码，其中我有一个枚举类似
枚举ADDR
{
一个= 0;
two = 1;
三= 2;
};
后来在代码中，我有一个返回ADDR类型的函数，它返回一个整数指的是正确的价值，但我想打印出一两个或三个名字。
我怎么能这样做，我的例子有很多案例所以不想使用
切换声明。
AFAIK在你的情况下是不可实现的（带枚举）。
为什么不使用地图？<最好的祝福，
J.Schafer
Kapil Khosla写道：
< blockquote class =post_quotes>
我有一个代码，其中我有一个枚举类似
枚举ADDR
{
一个= 0;
两个= 1;
三个= 2;
};
后来在代码中，我有一个fu返回一个ADDR类型，它返回一个指向正确值的整数，但我想打印出一个，两个或三个名字。
我怎么能这样做，我的例子有很多情况所以不想使用
开关语句。
你可以创建一个字符串表示数组：
const char * ADDR_strings [] = {" one"，" two"，" three" };
然后你可以这样做：
ADDR addr = get_the_addr（）;
std： ：cout<< ADDR_strings [addr]<< std :: endl;
" Kapil Khosla" < KH ********* @ yahoo.com> schrieb im Newsbeitrag
news：91 ************************** @ posting.google.c om ...
我有一个代码，其中我有一个枚举类似
枚举ADDR
{
一个= 0;
two = 1;
三= 2;
};
后来在代码中，我有一个返回ADDR类型的函数，它返回一个整数指的是正确的价值，但我想打印出一两个或三个名字。
我怎么能这样做，我的例子有很多案例所以不想使用
切换声明。
谢谢，
Kapil
我不知道任何解决方案没有''切换''或者std :: map带插入
为每个枚举器。
在我的应用程序中我使用这样的东西：
std： ：ostream的&安培; operator<<（std :: ostream& o，ADDR e）
{
switch（e）
{
案例一：return o<< 一个;
案例二：return o<< 两个;
案例三：return o<< 三;
}
}
格奥尔格
Hi,
I have a code in which I have an enum like
enum ADDR
{
one = 0;
two = 1;
three = 2;
};
Later in code , I have a function that returns an ADDR type, which
returns an integer referring to the correct value but I want to print
out the name one,two or three.
How can I do that, my example has a lot of cases so dont want to use a
switch statement.
Thanks,
Kapil
"Kapil Khosla" <kh*********@yahoo.com> wrote in message
news:91**************************@posting.google.c om...Hi,
I have a code in which I have an enum like
enum ADDR
{
one = 0;
two = 1;
three = 2;
};
Later in code , I have a function that returns an ADDR type, which
returns an integer referring to the correct value but I want to print
out the name one,two or three.
How can I do that, my example has a lot of cases so dont want to use a
switch statement.
AFAIK it''s not achievable in your case (with an enum).
Why not use a map?
With best wishes,
J.Schafer
Kapil Khosla wrote:
Hi,
I have a code in which I have an enum like
enum ADDR
{
one = 0;
two = 1;
three = 2;
};
Later in code , I have a function that returns an ADDR type, which
returns an integer referring to the correct value but I want to print
out the name one,two or three.
How can I do that, my example has a lot of cases so dont want to use a
switch statement.
You can make an array of the string representations:
const char* ADDR_strings[] = { "one", "two", "three" };
Then you can do something like:
ADDR addr = get_the_addr();
std::cout << ADDR_strings[addr] << std::endl;
"Kapil Khosla" <kh*********@yahoo.com> schrieb im Newsbeitrag
news:91**************************@posting.google.c om...Hi,
I have a code in which I have an enum like
enum ADDR
{
one = 0;
two = 1;
three = 2;
};
Later in code , I have a function that returns an ADDR type, which
returns an integer referring to the correct value but I want to print
out the name one,two or three.
How can I do that, my example has a lot of cases so dont want to use a
switch statement.
Thanks,
Kapil
I dont'' know any solution without a ''switch'' or a std::map with an insert
for each enumerator.
In my applications I use something like this:
std::ostream& operator <<( std::ostream& o, ADDR e )
{
switch( e )
{
case one: return o << "one";
case two: return o << "two";
case three: return o << "three";
}
}
Georg
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