指针和数组 [英] pointers and array
问题描述
如何使用双指针访问二维数组。
即int a [3] [3];
int ** p;
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-
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等
谢谢
Anthony
Anthony Moss写道：
如何使用双指针访问二维数组。
即int a [3] [3 ];
int ** p;
int（* p）[sizeof * a / sizeof ** a] = a;
< br $>
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pete
Anthony Moss写道：< blockquote class =post_quotes>如何使用双指针访问二维数组。
即int a [3] [3];
int ** p;
int（* p）[3];
示例：
#include< stdio .h>
int main（无效）
{
int a [3] [3] = {{1， 2,3}，{4,5,6}，{7 ，8,9}};
int（* p）[3];
p = a;
printf（" ; a [1] [1] =％d \ np [1] [1] =％d \ n，
a [1] [1]，p [1] [1] ）;
返回0;
}
-
Al Bowers
Tampa，Fl USA
mailto： xa ****** @ myrapidsys.com （删除x以发送电子邮件）
http：// www。 geocities.com/abowers822/
" Anthony Moss" < A * @ baesystems.com>。写道：
如何使用双指针访问二维数组。
即int a [3] [3];
int ** p;
你不是。如果你想使用a的子数组（很少见），你需要一个指向数组的指针：int（* p）[3]。如果，OTOH，你想与各个int成员一起工作
，你需要一个简单的int *。
声明int ** p意味着p是指针_to指针
int。你没有指向int的指针，所以你不应该使用
一个int **。
Richard
How do you use a double pointer to access a two dimensional array.
ie int a[3][3];
int **p;
-
-
-
-
-
etc.
thanks
Anthony
Anthony Moss wrote:
How do you use a double pointer to access a two dimensional array.
ie int a[3][3];
int **p;
int (*p)[sizeof *a / sizeof **a] = a;
--
pete
Anthony Moss wrote:How do you use a double pointer to access a two dimensional array.
ie int a[3][3];
int **p;
int (*p)[3];
Example:
#include <stdio.h>
int main(void)
{
int a[3][3] = {{1,2,3},{4,5,6},{7,8,9}};
int (*p)[3];
p = a;
printf("a[1][1] = %d\np[1][1] = %d\n",
a[1][1],p[1][1]);
return 0;
}
--
Al Bowers
Tampa, Fl USA
mailto: xa******@myrapidsys.com (remove the x to send email)
http://www.geocities.com/abowers822/
"Anthony Moss" <a.*@baesystems.com> wrote:
How do you use a double pointer to access a two dimensional array.
ie int a[3][3];
int **p;
You don''t. If you want to work with the sub-arrays of a (which is rare),
you need a pointer to an array: int (*p)[3]. If, OTOH, you want to work
with the individual int members, you need a simple int *.
The declaration int ** p means that p is a pointer _to a pointer_ to
int. You have no pointers to int to point at, so you should not be using
an int **.
Richard
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