将char *转换为char [英] Converting char* to char
问题描述
大家好，
我正在使用C ++ Builder5。我想从编辑框中获取数据，然后将
发送到开发工具包。开发工具包只能收到char
而且没有char *
这里是我代码的一部分：
char * Data_byte = 0x00;
UCHAR outBuffer [64];
WORD outPacketSize;
outBuffer [0] = Data_byte;
...
...
void __fastcall TForm1 :: Data_EditChange（TObject * Sender）
{
Data_byte = Data_Edit-> Text.c_str（）;
}
我收到错误 - > ;无法将char *转换为char。有没有人
有一个解决我的问题的方法？
所以我只需要从编辑框中获取一个字节并存储这个
in一个变量。
thnx提前，
克里斯
Chris在线写道：大家好，
我正在使用C ++ Builder5。我想从编辑框中获取数据并将其发送到开发工具包。开发工具包只能收到char
而且没有char *
这里是我代码的一部分：
char * Data_byte = 0x00;
UCHAR outBuffer [64];
WORD outPacketSize;
outBuffer [0] = Data_byte;
..
..
void __fastcall TForm1 :: Data_EditChange（TObject * Sender）
{Data_byte = Data_Edit-> Text.c_str（）;
}
我收到错误 - >无法将char *转换为char。有没有人能解决我的问题？
所以我只需要从编辑框中获取一个字节并将其存储在一个变量中。
thnx提前，
Chris
您需要检查文本的类型。来自
" Data_Edit"控制以查看字符串类型是否具有访问单个字符的
方法。如果
类型是std :: string，你可以使用：
{
Data_byte = Data_Edit-> Text [0];
}
但是，唉，Borland可能有自己的字符串类型。
您也可以在Borland新闻组发布。
查看下面的C ++ FAQ和welcome.txt
建议的新闻组。
-
Thomas Matthews
C ++新闻组欢迎辞：
http://www.slack.net/~shiva/welcome.txt
C ++常见问题： http://www.parashift.com/c++-faq-lite
C常见问题：< a rel =nofollowhref =http://www.eskimo.com/~scs/c-faq/top.htmltarget =_ blank> http://www.eskimo.com/~scs/c -faq / top.html
alt.comp.lang.learn.c-c ++ faq：
http：// w ww.raos.demon.uk/acllc-c++/faq.html
其他网站：
http://www.josuttis.com - C ++ STL图书馆书籍
Chris Online写道：
char * Data_byte = 0x00;
UCHAR outBuffer [64];
WORD outPacketSize;
outBuffer [0] = Data_byte;
你想在这做什么？你想要投入什么价值
outBuffer [0]以及为什么？
" Chris Online" ; < CV ******* @ hotmail.com>在消息中写道
news：87 ************************** @ posting.google.c om ...大家好，我正在使用C ++ Builder5。我想从编辑框中获取数据并将其发送到开发工具包。开发工具包只能接收char
而且没有char *
这里是我的代码的一部分：
char * Data_byte = 0x00;
我假设这是一个错误的类型
char Data_byte = 0x00;
UCHAR outBuffer [ 64];
WORD outPacketSize;
outBuffer [0] = Data_byte;
..
..
void __fastcall TForm1 :: Data_EditChange（TObject * Sender）
{
Data_byte = Data_Edit-> Text.c_str（）;
}
我收到错误 - >无法将char *转换为char。有没有人能解决我的问题？
所以我只需要从编辑框中获取一个字节并将其存储在一个变量中。
好好想想吧。编辑框可以包含多个字符这就是为什么
Data_Edit-> Text是一个字符串（可能，你没说）。你想要一个
字符，但是哪一个？第一个，第二个，最后一个，第一个
这不是一个空间，到底是什么？这不仅仅是关于我如何将
a char *转换为char，没有通用的方法可以做到这一点，这是一个定义你的b
$ b问题更清楚一点。
FWIW您可以使用[]运算符索引字符串
Data_byte = Data_Edit-> Text [0 ] //字符串中的第一个字符
thnx提前，
Chris
john
Hi all,
I''m using C++ Builder5. I want to get data from an edit-box and
send it to a development kit. The dev-kit can only receive char
and no char*
here''s a part of my code:
char* Data_byte = 0x00;
UCHAR outBuffer[64];
WORD outPacketSize;
outBuffer[0] = Data_byte;
...
...
void __fastcall TForm1::Data_EditChange(TObject *Sender)
{
Data_byte=Data_Edit->Text.c_str();
}
I get an error -> Can''t convert char* to char. Does anyone
have a solution for my problem?
So I just need to get a byte from the edit-box and store this
in a variable.
thnx in advance,
Chris
Chris Online wrote:Hi all,
I''m using C++ Builder5. I want to get data from an edit-box and
send it to a development kit. The dev-kit can only receive char
and no char*
here''s a part of my code:
char* Data_byte = 0x00;
UCHAR outBuffer[64];
WORD outPacketSize;
outBuffer[0] = Data_byte;
..
..
void __fastcall TForm1::Data_EditChange(TObject *Sender)
{
Data_byte=Data_Edit->Text.c_str();
}
I get an error -> Can''t convert char* to char. Does anyone
have a solution for my problem?
So I just need to get a byte from the edit-box and store this
in a variable.
thnx in advance,
Chris
You will need to check the type of "Text" from the
"Data_Edit" control to see if the string type has a
method to access individual characters. If the
type was std::string, you could use:
{
Data_byte = Data_Edit->Text[0];
}
But alas, Borland may have its own string type.
You could also post this at a Borland newsgroup.
Check the C++ FAQ and welcome.txt below for
suggested newsgroups.
--
Thomas Matthews
C++ newsgroup welcome message:
http://www.slack.net/~shiva/welcome.txt
C++ Faq: http://www.parashift.com/c++-faq-lite
C Faq: http://www.eskimo.com/~scs/c-faq/top.html
alt.comp.lang.learn.c-c++ faq:
http://www.raos.demon.uk/acllc-c++/faq.html
Other sites:
http://www.josuttis.com -- C++ STL Library book
Chris Online wrote:
char* Data_byte = 0x00;
UCHAR outBuffer[64];
WORD outPacketSize;
outBuffer[0] = Data_byte;
What are you trying to do here? What value are you trying to put into
outBuffer[0] and why?
"Chris Online" <cv*******@hotmail.com> wrote in message
news:87**************************@posting.google.c om...Hi all,
I''m using C++ Builder5. I want to get data from an edit-box and
send it to a development kit. The dev-kit can only receive char
and no char*
here''s a part of my code:
char* Data_byte = 0x00;
I''m assuming this is a mistype for
char Data_byte = 0x00;
UCHAR outBuffer[64];
WORD outPacketSize;
outBuffer[0] = Data_byte;
..
..
void __fastcall TForm1::Data_EditChange(TObject *Sender)
{
Data_byte=Data_Edit->Text.c_str();
}
I get an error -> Can''t convert char* to char. Does anyone
have a solution for my problem?
So I just need to get a byte from the edit-box and store this
in a variable.
Well think about it. An edit box can contain multiple characters That''s why
Data_Edit->Text is a string (probably, you didn''t say). You want one
character, but which one? The first, the second, the last, the first one
that isn''t a space, what exactly? It''s not just a matter of how do I convert
a char* to a char, there is no universal way to do that, its a matter of
defining your problem a little more clearly.
FWIW you can index a string using the [] operator
Data_byte = Data_Edit->Text[0] // the first character from the string
thnx in advance,
Chris
john
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