奇闻趣事，请帮帮我 [英] Gonzo, help me please

问题描述

我想要编写一个程序，要求用户输入两个整数。然后程序将询问用户四个字母a中的一个来添加数字，s来减去数字，m来乘以数字，或者d来分割这两个数字。

如果用户输入除列出的4个字符以外的任何字符，请不断询问它们，直到输入正确的字母为止。在显示器上显示两个数字输入使用的数学运算和操作的答案：


你的目标名称是什么？ PM它

I''m suppose to write a program that will ask the user to enter two integers. Then the program will ask the user for one of four letters a to add the numbers, s to subtract the numbers, m to multiply the numbers, or d to divide the two numbers.
If the user enters any character other than the 4 listed, keep asking them over and over until they enter a correct letter. Display on the monitor the two numbers entered the math operation used and the answer of the operation:

What''s your aim name? PM it

推荐答案

是否应该对数字进行任何错误检查？或者只是为了字母？


你需要做的就是两个数字，然后输入一个while循环。 while循环将具有char i ==''''或i =='s''或i ==''m''或i ==''d''的条件。当你在那个循环中，cin i。


然后，你可以使用if语句或switch语句来执行正确的操作。

Is there supposed to be any error-checking for the numbers? Or just for the letters?

All you need to do is cin two numbers, then enter a while loop. The while loop will have a condition that a char i == ''a'' or i == ''s'' or i == ''m'' or i == ''d''. While you are in that loop, cin i.

Then, you can either use if statements or a switch statement to do the correct operation.

是否应该对数字进行任何错误检查？或者只是为了字母？


你需要做的就是两个数字，然后输入一个while循环。 while循环将具有char i ==''''或i =='s''或i ==''m''或i ==''d''的条件。当你在那个循环中时，cin i。


然后，你可以使用if语句或switch语句来执行正确的操作。

Is there supposed to be any error-checking for the numbers? Or just for the letters?

All you need to do is cin two numbers, then enter a while loop. The while loop will have a condition that a char i == ''a'' or i == ''s'' or i == ''m'' or i == ''d''. While you are in that loop, cin i.

Then, you can either use if statements or a switch statement to do the correct operation.

只是字母

Just the letters

那么你就明白了。

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