扭转数字的数字 [英] to reverse the digits of a number
问题描述
你能告诉我以下代码有什么问题吗？
给出了
a简单的输入值，如：10001,10032,10432，一切似乎都是
工作得很好，但在给出输入值如
43211它没有用，有些价值的'' - ''标志在它之前
显示。
i hve。尝试使用long int也是如此。
| void main（）
| {
| clrscr（）;
| int a，i，d，sum = 10000，sum1 = 0;
| printf（输入您选择的五位数：）;
| scanf（"％d"& a）;
|
| for（i = 0; i< = 4; i ++）
| {
| d = a％10;
| a = a / 10;
| d = d *总和;
| sum1 = sum1 + d;
| sum = sum / 10;
| printf（"％d \ nn"，sum1）;
| }
|的printf（QUOT;％d" \\\
"，SUM1）;
|的getch（）;
| }
dipti写道：请你们告诉我什么是错的使用以下代码
| void main（）
^^^^
已经死了。 main的返回类型为int | {
| clrscr（）;
^^^^^^
再次死亡。不仅clrscr（）不是标准函数，那么
在代码中没有声明或定义，甚至没有包含
非标准头文件。 | int a，i，d，sum = 10000，sum1 = 0;
| printf（输入你选择的五位数：）;
^^^^^^
再次死亡。没有声明，甚至没有包含< stdio.h> |的scanf（QUOT;％d"，&安培;一个）;
^^^^^
再次死亡。没有声明，甚至没有包含< stdio.h>
此外，提示后面既没有''\ n''也没有打电话给
''fflush（stdout）;''因此没有理由认为提示出现了。 |
| for（i = 0; i <= 4; i ++）
| {
| d = a％10;
| A = A / 10;
a / = 10;如果没有对|的两个引用，也会这样做d = d *总和;
| sum1 = sum1 + d;
|总和=总和/ 10;
这看起来不连贯。
看起来你真的想要像
这样的代码[而不是整个（i ...循环）
if（a< 0）{
putchar（'' - ''）;
a = -a;
}
sum = 0;
而（a）{
sum * = 10;
sum + = a ％10;
a / = 10;
printf（"％d \ nn"，sum）;
}
| printf（"％d \ n"，sum1）;
|}
| printf（"％d" \ n"，sum1）;
这是不必要的。 | getch（）;
再次死亡。不仅getch（）不是标准函数，还有
代码中没有声明或定义，甚至没有包含
a非标准标题。
如果你不使用C99编译器，你需要（并且应该使用C99编译器，甚至是
） ）
返回0;
|}
dipti写道：请你们告诉我以下代码有什么问题
就像给出一个简单的输入值一样：10001,10032,10432，一切似乎都很好
工作正常但是在给出一个输入值，比如
43211它不起作用，前面带有'' - ''符号的一些值得到
我只是尝试了这个特定的输入，它给了我正确的输出
（使用VS 2005），您是否有机会使用旧的16位编译器？
显示。
我好。尝试使用long int也是这样。
它没有什么区别，它们是32位
编译器的32位大小...
Abdo Haji-Ali
程序员
In | Framez
dipti写道：请你们告诉我以下代码有什么问题
给出一个简单的输入值，如：10001,10032,10432，一切似乎都工作正常，但在给出输入值如
43211它不起作用，有些价值' ' - ''之前的标志是获得
我只是尝试了这个特定的输入并且它给了我正确的结果
（使用VS 2005），你是否有机会使用16位编译器？
显示。
我好。尝试使用long int也是这样。
32位编译器的32位大小相同......
[code]
Abdo Haji-Ali
程序员
In | Framez
Hi, Can u guys please tell me what''s wrong with the following code
as on giving
a simple input value like: 10001, 10032, 10432, everything seems to be
working fine but on giving a input value like
43211 it''s not working,some value with ''-'' sign preceding it is getting
display.
i hve. tried this using long int also.
| void main()
| {
| clrscr();
| int a,i,d,sum=10000,sum1=0;
| printf("Enter A Five Digit No.of Your Choice:");
| scanf("%d",&a);
|
| for(i=0;i<=4;i++)
| {
| d=a%10;
| a=a/10;
| d=d*sum;
| sum1=sum1+d;
| sum=sum/10;
| printf("%d\n",sum1);
| }
| printf("%d"\n",sum1);
| getch();
| }
dipti wrote:Hi, Can u guys please tell me what''s wrong with the following code | void main() ^^^^
dead already. main has a return type of int | {
| clrscr(); ^^^^^^
dead again. Not only is clrscr() not a standard function, there
is no declaration or definition in your code, not even the inclusion of
a non-standard header. | int a,i,d,sum=10000,sum1=0;
| printf("Enter A Five Digit No.of Your Choice:"); ^^^^^^
dead again. No declaration, not even the inclusion of <stdio.h> | scanf("%d",&a); ^^^^^
dead again. No declaration, not even the inclusion of <stdio.h>
In addition, the prompt is followed by neither a ''\n'' nor call to
''fflush(stdout);'' so there is no reason to suppose the prompt appears. |
| for(i=0;i<=4;i++)
| {
| d=a%10;
| a=a/10; a /= 10; would do as well, without the two references to a | d=d*sum;
| sum1=sum1+d;
| sum=sum/10; This looks incoherent.
It would seem that you actually want code like
[instead of the whole for(i... loop]
if (a < 0) {
putchar(''-'');
a = -a;
}
sum = 0;
while(a) {
sum *= 10;
sum += a%10;
a /= 10;
printf("%d\n",sum);
}
| printf("%d\n",sum1);
| }
| printf("%d"\n",sum1); And this is unneeded. | getch(); dead again. Not only is getch() not a standard function, there
is no declaration or definition in your code, not even the inclusion of
a non-standard header.
If you are not using a C99 compiler, you need (and should have, even
using a C99 compiler)
return 0;
| }
dipti wrote:Hi, Can u guys please tell me what''s wrong with the following code
as on giving
a simple input value like: 10001, 10032, 10432, everything seems to be
working fine but on giving a input value like
43211 it''s not working,some value with ''-'' sign preceding it is getting I just tried this specific input and it gave me the correct ouput
(using VS 2005), are you by any chance using an old 16-bit compiler?
display.
i hve. tried this using long int also.
It won''t make a difference, they are the both 32-bit size on a 32-bit
compiler...
Abdo Haji-Ali
Programmer
In|Framez
dipti wrote:Hi, Can u guys please tell me what''s wrong with the following code
as on giving
a simple input value like: 10001, 10032, 10432, everything seems to be
working fine but on giving a input value like
43211 it''s not working,some value with ''-'' sign preceding it is getting I just tried this specifc input and it gave me the correct results
(using VS 2005), are you by any chance using a 16-bit compiler?
display.
i hve. tried this using long int also.
It''s the same both are 32-bit size on a 32-bit compiler...
[code]
Abdo Haji-Ali
Programmer
In|Framez
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