将DateTime转换为Unixdatetime [英] Convert DateTime to Unixdatetime
问题描述
我有一些代码可以将日期转换为unixdatetime表示形式(自1970年以来数字
秒)。唯一的问题是它只计算整个
天,它忽略了时间部分。所以转换为1/1/1970和1/1/1970 8:00:00 AM
都返回0但是最后应该返回28800.
我的代码:
尝试
Dim dte As DateTime
dte = DateTime.Parse(CmdArgs(1))
Console.WriteLine(DateDiff(DateInterval.Second,
#1/1/1970#,dte))
Catch ex As Exception
控制台.WriteLine(ex.Message)
结束尝试
当我尝试将12:00:00 AM添加到DateDiff funcion vs.net中的日期
删除它。
任何想法?
I have some code to convert a date to the unixdatetime representation (number
of seconds since 1970). Only problem is that it only counts from the whole
day, it ignores the times part. So convert 1/1/1970 and 1/1/1970 8:00:00 AM
both return 0 but the last should return 28800.
My code:
Try
Dim dte As DateTime
dte = DateTime.Parse(CmdArgs(1))
Console.WriteLine(DateDiff(DateInterval.Second,
#1/1/1970#, dte))
Catch ex As Exception
Console.WriteLine(ex.Message)
End Try
When I try to add 12:00:00 AM to the date in the DateDiff funcion vs.net
removes that.
Any ideas?
推荐答案
菲尔,
我再次测试了你在上一个问题中向我展示过的方法。
显示28800,显示您显示的值现在。
我希望这会有所帮助,
Cor
Phil,
I tested again the method I showed you in your previous question about that.
It shows 28800 with the values you show now.
I hope this helps,
Cor
" Philip瓦赫纳尔" < pH值************* @ online.nospam> schrieb
"Philip Wagenaar" <ph*************@online.nospam> schrieb
我有一些代码将日期转换为unixdatetime
表示(自1970年以来的秒数)。唯一的问题是,它只计算一整天,它忽略了时代的一部分。所以
转换为1/1/1970和1/1/1970 8:00:00 AM都返回0但是最后
应该返回28800.
我的代码:
尝试
Dim dte As DateTime
dte = DateTime.Parse(CmdArgs(1))
cmdargs(1)包含什么*确切*? br />
Console.WriteLine(DateDiff(DateInterval.Second,#1/1/1970#,dte))
Catch ex As Exception> Console.WriteLine(ex.Message)
结束尝试
当我尝试将12:00:00 AM添加到DateDiff功能的日期时
vs.net删除它。
12:00 AM是午夜。这是* display *是可选的。 #1/1/1970 12:00 AM#和
#1/1/1970#是相同的值。
有什么想法吗?
I have some code to convert a date to the unixdatetime
representation (number of seconds since 1970). Only problem is that
it only counts from the whole day, it ignores the times part. So
convert 1/1/1970 and 1/1/1970 8:00:00 AM both return 0 but the last
should return 28800.
My code:
Try
Dim dte As DateTime
dte = DateTime.Parse(CmdArgs(1))
What *exactly* does cmdargs(1) contain?
Console.WriteLine(DateDiff(DateInterval.Second, #1/1/1970#, dte))
Catch ex As Exception
Console.WriteLine(ex.Message)
End Try
When I try to add 12:00:00 AM to the date in the DateDiff funcion
vs.net removes that.
12:00 AM is midnight. It''s *display* is optional. #1/1/1970 12:00 AM# and
#1/1/1970# are identical values.
Any ideas?
使用我前几天给你的解决方案:
dim diff as double
diff = yourdate.subtract(# 1970年1月1日#)。totalseconds
Armin
Use the solution I already gave you some days ago:
dim diff as double
diff = yourdate.subtract(#1/1/1970#).totalseconds
Armin
使用命令行应用程序尝试此操作:
尝试
Dim dte As DateTime
dte = DateTime.Parse(CmdArgs(1))
Console.WriteLine(CType(dte) .Subtract(New
System.DateTime(1970,1,1)),TimeSpan).TotalSeconds.ToString())
Catch ex As Exception
Console.WriteLine(ex.Message)
结束尝试
似乎将命令行参数转换为datetime是错误的。
对此有何看法?
" Cor Ligthert [MVP]"写道:
Cor try this with command line app:
Try
Dim dte As DateTime
dte = DateTime.Parse(CmdArgs(1))
Console.WriteLine(CType(dte.Subtract(New
System.DateTime(1970, 1, 1)), TimeSpan).TotalSeconds.ToString())
Catch ex As Exception
Console.WriteLine(ex.Message)
End Try
Seems that conversion of commandline argument to datetime is going wrong.
Any thoughts on that?
"Cor Ligthert [MVP]" wrote:
菲尔,
我再次测试了你在上一个问题中向我展示的方法。
它显示28800你现在展示的价值观。
我希望这会有所帮助,
>
这篇关于将DateTime转换为Unixdatetime的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!