获取指针的地址 [英] Getting the address of a pointer

问题描述

我怀疑ASP.NET

应用程序中的两个用户（因此线程）正在共享相同的指针 - 他们不应该这样做！对我来说可能最简单的调试方法是比较

指针的地址，但是VB.NET丢失了ObjPtr所以这有点棘手。


有没有办法调试这样的变量/指针的地址？


谢谢，Rob。

解决方案

你好Rob，


目前我在这个问题上找到了一位支持专家。当

任何更新时，我们会在第一时间回复。


最好的问候，

Wei-Dong XU

Microsoft产品支持服务

此帖子按原样提供。没有保证，也没有赋予任何权利。

我很乐意为您提供帮助。

Rob，

Rob Nicholson <在****** @ community.nospam> schrieb：

我怀疑ASP.NET
应用程序中的两个用户（以及线程）共享相同的指针 - 他们不应该这样做！对我来说可能最简单的调试方法是比较
指针的地址，但是VB.NET丢失了ObjPtr，所以这有点棘手。

你在谈论什么指针？你在处理非托管代码吗？


-

MS Herfried K. Wagner

MVP< URL：http：/ /dotnet.mvps.org/>

VB< URL：http：//classicvb.org/petition/>

>目前我在这个问题上找到了一位支持专业人员。

当

任何更新时，我们会在第一时间回复。

嗨 - 现在没关系谢谢。我不需要在

结束时打印出地址 - 这只是我的旧方法。显示通过查看十六进制数来检查指针:-)我能够简单地？Ptr1是Ptr2。在命令

窗口中实现相同的结果。


谢谢，Rob。

I''ve got a suspicion that two user (and therefore threads) in an ASP.NET
application are sharing the same pointers - which they shouldn''t be! The
easiest way for me to possibly debug this is to compare the addresses of the
pointers but VB.NET has lost ObjPtr so this is a bit tricky.

Is there a way to debug the address of a variable/pointers like this?

Thanks, Rob.

解决方案

Hi Rob,

Currently I am finding one support professional for you on this issue. When
any update, we will reply here at the first time.

Best Regards,
Wei-Dong XU
Microsoft Product Support Services
This posting is provided "AS IS" with no warranties, and confers no rights.
It is my pleasure to be of assistance.

Rob,

"Rob Nicholson" <in******@community.nospam> schrieb:

I''ve got a suspicion that two user (and therefore threads) in an ASP.NET
application are sharing the same pointers - which they shouldn''t be! The
easiest way for me to possibly debug this is to compare the addresses of
the
pointers but VB.NET has lost ObjPtr so this is a bit tricky.

What pointers are you talking about? Are you dealing with unmanaged code?

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://classicvb.org/petition/>

> Currently I am finding one support professional for you on this issue.
When

any update, we will reply here at the first time.

Hi - doesn''t matter now thanks. I didn''t need to print out the address in
the end - that was just my "old ways" showing whereby looking at hex numbers
to check pointers :-) I was able to simply "?Ptr1 is Ptr2" in the command
window to achieve the same result.

Thanks, Rob.

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