Javascript函数确定一个点是否在矩形之间 [英] Javascript function to determine if a point is in between a rectangle

问题描述

我有一个Javascript函数，它没有返回我预期的结果。我试图确定基于2个其他x，y点的矩形内是否存在x，y点。在我的代码中，x和y是有问题的原始点。 z1和z2是矩形的左上角坐标，z3和z4是右下角的坐标。

I have a Javascript function that isn't returning the result I expected. I am trying to determine if an x,y point exists within a rectangle based on 2 other x,y points. In my code x and y are the original point in question. z1 and z2 are the top left coordinates of the rectangle and z3 and z4 are the bottom right coordinates.

function isInside(x,y,z1,z2,z3,z4){
x1 = Math.min(z1, z3);
x2 = Math.max(z1, z3);
y1 = Math.min(z2, z4);
y2 = Math.max(z2, z4);
if ((x1 <= x <= x2) && (y1 <= y <= y2)) {
 console.log (x1 + "," + x + "," + x2); 
 console.log (y1 + "," + y + "," + y2);
 return true;
} else {
 return false;
};
};

如果我评价isInside（110,175,50,50,100,100）我会变成现实。这是出乎意料的，因为点150,175不存在于50,50和100,100的矩形内。任何帮助将不胜感激。

If I evaluate isInside(110,175,50,50,100,100) I am getting true. This is unexpected as point 110,175 does not exist within a rectangle of 50,50 and 100,100. Any help would be appreciated.

推荐答案

（x1< = x< = x2）无法在Javascript中执行您想要的操作：您必须使用 x1< = x&& x< = x2 。

(x1 <= x <= x2) doesn't do what you want it to do in Javascript: you have to use x1 <= x && x <= x2.

如果您插入这些变量的实际数字并在Chrome的控制台中尝试这一点，您可以看到整个语句总是评估为真：

If you plug in actual numbers in for those variables and try this out in Chrome's console, you can see that the whole statement always evaluates to true:

1 <= 3 <= 5
true
9 <= 3 <= 5
true

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