每个星期的一周 [英] Week of the month
问题描述
嗨
我有一份报告，其中列出了各个日期的工作时间。什么可以是
方式为每个条目分配
条目的日期所属的月份？
谢谢
问候
月份定义为;
如果date1是第一个条目的日期，那么
date1 - date1 + 6 =第1周
date1 + 7 - date1 + 13 = week 2
等...
我可以看到有点棘手，因为date1可能是任何东西取决于
报告输入查询..
问候
" John" <乔** @ nospam.infovis.co.uk>在留言中写道
news：41 *********************** @ news-text.dial.pipex.com ...嗨
我有一份报告，其中列出了各个日期的工作时间。什么可能是
分配每个条目的方式，该日期为
条目所属的月份？
谢谢
John写道：
月份定义为;
如果date1是第一个条目的日期，那么
date1 - date1 + 6 =第1周
date1 + 7 - date1 + 13 =第2周
等等on ..
我可以看到有点棘手，因为date1可以是任何取决于
报告输入查询的东西..
问候
约翰 <乔** @ nospam.infovis.co.uk>在消息中写道
新闻：41 *********************** @ news-text.dial.pipex.com ...
嗨
我有一份报告，其中列出了各个日期的工作时间。什么可能是
分配每个条目的方式，该日期为
条目所属的月份？
谢谢
这里我使用10/1/2004作为开始日期。我减去
开始/结束之间的天数，除以7得到一周，然后加1来得到一周所以
表示周数从1开始，而不是0.
''周的日期与开始日相同
？ dateiff（d，＃10/1/2004＃，＃10/1/2004＃+ 7）\7 + 1
1
''周7天外出
？ dateiff（d，＃10/1/2004＃，＃10/1/2004＃+ 7）\7 + 1
2
"约翰" <乔** @ nospam.infovis.co.uk>在留言中写道
news：41 *********************** @ news-text.dial.pipex.com ...嗨
我有一份报告，其中列出了各个日期的工作时间。什么可能是
分配每个条目的方式，该日期为
条目所属的月份？
谢谢
创建一个表来保存所有不同的时间段 - 在这种情况下是几周。
用正确的周数标记每一行并加入在
的新表中查询。
Hi
I have a report which lists staff hours for various dates. What could be a
way to assign to each entry the week of the month that the date for the
entry belongs to?
Thanks
Regards
Week of month defined as;
if date1 is date from the first entry whatever it is then
date1 - date1+6 = week 1
date1+7 - date1+13 = week 2
and so on..
Slightly tricky I can see, as date1 could be anything depending on the
report input query..
Regards
"John" <Jo**@nospam.infovis.co.uk> wrote in message
news:41***********************@news-text.dial.pipex.com...Hi
I have a report which lists staff hours for various dates. What could be a
way to assign to each entry the week of the month that the date for the
entry belongs to?
Thanks
Regards
John wrote:
Week of month defined as;
if date1 is date from the first entry whatever it is then
date1 - date1+6 = week 1
date1+7 - date1+13 = week 2
and so on..
Slightly tricky I can see, as date1 could be anything depending on the
report input query..
Regards
"John" <Jo**@nospam.infovis.co.uk> wrote in message
news:41***********************@news-text.dial.pipex.com...Hi
I have a report which lists staff hours for various dates. What could be a
way to assign to each entry the week of the month that the date for the
entry belongs to?
Thanks
Regards
Here I use 10/1/2004 as the start date. I subtract the days between
start/end, divide by 7 to get the week, and add 1 to get the week so
that the number of the week starts at 1, not 0.
''week where date is same as start day
? datediff("d",#10/1/2004#,#10/1/2004#+7)\7 + 1
1
''week 7 days out
? datediff("d",#10/1/2004#,#10/1/2004#+7)\7 + 1
2
"John" <Jo**@nospam.infovis.co.uk> wrote in message
news:41***********************@news-text.dial.pipex.com...Hi
I have a report which lists staff hours for various dates. What could be a
way to assign to each entry the week of the month that the date for the
entry belongs to?
Thanks
Regards
Create a table to hold all your distinct time periods - in this case weeks.
Label each row with the correct week number and join to the new table in
your queries.
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