以某种方式定义一个具有自己类型的结构作为字段？ [英] define a struct that has its own type as a field somehow?

问题描述

你好，


是否可以定义一个自身类型的结构？


所以它可以和如果是这样怎么做我想在这里做的事情？：


typedef struct mystruct {

int a;

mystruct * b;

} mystruct;


以上都行不通：


test。 c：7：未定义类型，找到`mystruct''

cpp-precomp：警告：智能预处理时出错，重试

基本模式

test.c：在函数main中：

test.c：7：在mystruct之前解析错误

test.c：7：警告：否结构或联合结束时的分号

test.c：顶级：

test.c：8：警告：数据定义没有类型或存储类

test.c：10：在返回之前解析错误


谢谢，本。

Hello,

Is it possible to define a struct that has a type of itself in it?

So is it possible and if so how to do what I''m trying to do here?:

typedef struct mystruct {
int a;
mystruct *b;
} mystruct;

The above doesn''t work:

test.c:7: undefined type, found `mystruct''
cpp-precomp: warning: errors during smart preprocessing, retrying in
basic mode
test.c: In function `main'':
test.c:7: parse error before "mystruct"
test.c:7: warning: no semicolon at end of struct or union
test.c: At top level:
test.c:8: warning: data definition has no type or storage class
test.c:10: parse error before "return"

Thanks, Ben.

推荐答案

" Ben" < [e-mail] in message news：26 ****************** @ x.abc ...

"Ben" <[e-mail] in message news:26******************@x.abc...

您好，


是否可以定义一个自身类型的结构？

谢谢，Ben。

Hello,

Is it possible to define a struct that has a type of itself in it?
Thanks, Ben.

试试这个

typedef struct _mystruct {

int a;

struct _mystruct * b;

} mystruct;


Serafeim

Try this
typedef struct _mystruct {
int a;
struct _mystruct *b;
} mystruct;

Serafeim

文章< 26 ** ****************@x.abc>，Ben< [e-mail]：

In article <26******************@x.abc>, Ben <[e-mail]:

您好，


是否可以定义一个具有自身类型的结构？


那么它是否有可能如果可以的话怎么做我想在这里做？：


typedef struct mystruct {

int a;

mystruct * b; < br $>
} mystruct;


以上都行不通：


test.c：7：未定义类型，发现`mystruct''

cpp-precomp：警告：智能预处理过程中的错误，重试

基本模式

test.c：In函数`main''：

test.c：7：在mystruct之前解析错误

test.c：7：警告：str结束时没有分号uct或union

test.c：顶级：

test.c：8：警告：数据定义没有类型或存储类

test.c：10：在返回之前解析错误


谢谢，Ben。

Hello,

Is it possible to define a struct that has a type of itself in it?

So is it possible and if so how to do what I''m trying to do here?:

typedef struct mystruct {
int a;
mystruct *b;
} mystruct;

The above doesn''t work:

test.c:7: undefined type, found `mystruct''
cpp-precomp: warning: errors during smart preprocessing, retrying in
basic mode
test.c: In function `main'':
test.c:7: parse error before "mystruct"
test.c:7: warning: no semicolon at end of struct or union
test.c: At top level:
test.c:8: warning: data definition has no type or storage class
test.c:10: parse error before "return"

Thanks, Ben.

糟糕，我刚刚在K& R书中找到了一个名为

" Self-referential Structures" ！ :)我认为这将回答

问题......而且确实如此。答案是：


struct mystruct {

int a;

struct mystruct * b;

};

Oops, I''ve just found a section in the K&R book titled
"Self-referential Structures" ! :) I think that will answer the
question... and it does. The answer is:

struct mystruct {
int a;
struct mystruct *b;
};

在文章< eh *********** @ ulysses.noc.ntua.gr> ;, Papastefanos Serafeim

< se ****** @ otenet.grwrote：

In article <eh***********@ulysses.noc.ntua.gr>, Papastefanos Serafeim
<se******@otenet.grwrote:

" Ben" < [e-mail] in message news：26 ****************** @ x.abc ...

"Ben" <[e-mail] in message news:26******************@x.abc...

您好，


是否可以定义一个自身类型的结构？

谢谢，Ben。

Hello,

Is it possible to define a struct that has a type of itself in it?
Thanks, Ben.

试试这个

typedef struct _mystruct {

int a;

struct _mystruct * b;

} mystruct;


Serafeim

Try this
typedef struct _mystruct {
int a;
struct _mystruct *b;
} mystruct;

Serafeim

是的，谢谢。 ''struct''面前做到了。

谢谢，Ben。

Yup, thanks. ''struct'' infront does it.
Thanks, Ben.

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