简单代码的奇怪问题 [英] Curious issue with simple code

问题描述

我有一些简单的代码 - 有效......有点代码：

Hi,

I have some simple code - which works...kind of..here''s the code:

展开 | 选择 | Wrap | 行号

推荐答案

codefire写道：

codefire wrote:

我有一些简单的代码 - 有效......有点代码：

Hi,

I have some simple code - which works...kind of..here''s the code:

展开 | 选择 | Wrap | 行号

codefire写道：

codefire wrote:

如上所述，它们都按预期工作。但是，在标记的行上，如果我使用f代替fp，那么该条件将返回false！当然，

isfile（f）应该返回true，即使我只是给出了一个文件名，而不是完整路径的
？

As above it all works as expected. However, on the marked line, if I
use f instead of fp then that condition returns false! Surely,
isfile(f) should return true, even if I just give a filename, rather
than the full path?

尝试打印两个f和fp，看看你能分辨两个文件名之间的区别

......


< / F>

try printing both "f" and "fp", and see if you can tell the difference
between the two filenames...

</F>

codefire写道：

codefire wrote:

如上所述，它们都按预期工作。但是，在标记的行上，如果我使用f代替fp，那么该条件将返回false！当然，

isfile（f）应该返回true，即使我只是给出了一个文件名，而不是完整路径的
？

As above it all works as expected. However, on the marked line, if I
use f instead of fp then that condition returns false! Surely,
isfile(f) should return true, even if I just give a filename, rather
than the full path?

嗨Tony，


实际上该文件与工作目录不同

目录，所以你需要给它找到它的路径。如果你从'c：\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ >

问候，

乔丹

Hi Tony,

Actually the file is in a different directory from the working
directory, so you need to give it the path where to find it. If you
started the script from ''c:\intent\docn'' (i.e., start_dir), then just
using f would work.

Regards,
Jordan

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