cURL返回上一个有效网址，但不下载内容？ [英] cURL return last effective url, but don't download content?

问题描述

假设我有类似的东西


$ resource = curl_init（）;

curl_setopt（$ resource，CURLOPT_FOLLOWLOCATION，TRUE）;

curl_setopt（$ resource，CURLOPT_RETURNTRANSFER，TRUE）;

curl_setopt（$ resource，CURLOPT_URL，''......''）;

curl_exec （$ resource）;

$ lastUrl = curl_getinfo（$ resource，CURLINFO_EFFECTIVE_URL）;

curl_close（$ resource）;


我只对$ lastUrl地址感兴趣。是否可以在没有

的情况下下载实际转移时浪费带宽？

地址？


将RETURNTRANSFER设置为FALSE输出直接转移

Suppose I have something like this

$resource = curl_init();
curl_setopt($resource, CURLOPT_FOLLOWLOCATION, TRUE);
curl_setopt($resource, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($resource, CURLOPT_URL, ''......'');
curl_exec($resource);
$lastUrl = curl_getinfo($resource, CURLINFO_EFFECTIVE_URL);
curl_close($resource);

I''m only interested in the $lastUrl address. Is it possible without
wasting bandwidth on downloading the actual trasfer which is at that
address?

Setting RETURNTRANSFER to FALSE outputs transfer directly

推荐答案

resource = curl_init（）;

curl_setopt（

resource = curl_init();
curl_setopt(

资源，CURLOPT_FOLLOWLOCATION，TRUE）;

curl_setopt（

resource, CURLOPT_FOLLOWLOCATION, TRUE);
curl_setopt(

资源，CURLOPT_RETURNTRANSFER，TRUE）;

curl_setopt（

resource, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt(

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