组合数量 [英] Number of combinations
问题描述
我的数组如下：
arr1 = {a，b，c}
arr2 = {1,2， 3}
arr3 = {x，y，z}
我想得到这些数组的组合，如下所示
arr_result = {a1x，a1y，a1z，a2x，a2y，a2z，a3x，a3y，
a3z，
b1x，b1y，b1z，b2x，b2y，b2z， ; B3X" ;,
" b3y"，" B3Z" ;,
" C1X"，" C1Y"，" C1Z"，" C2X" ;, " c2y"，" c2z"，" c3x"，
" c3y"，" c3z"}
感谢有人可以提供帮助用例子算法。
谢谢！
Hi,
I have arrays below:
arr1 = { a, b, c}
arr2 = {1, 2, 3}
arr3 = {x, y, z}
I want to get a combination of these array, as below
arr_result = { "a1x", "a1y", "a1z", "a2x", "a2y", "a2z", "a3x", "a3y",
"a3z",
"b1x", "b1y", "b1z", "b2x", "b2y", "b2z", "b3x",
"b3y", "b3z",
"c1x", "c1y", "c1z", "c2x", "c2y", "c2z", "c3x",
"c3y", "c3z"}
appreciate if someone can help with example algorithm.
Thanks!
推荐答案
6月14日，12：16 pm，csfon ... @ gmail.com写道：
On Jun 14, 12:16 pm, csfon...@gmail.com wrote:
我有以下数组：
arr1 = {a，b，c}
arr2 = {1,2,3}
arr3 = {x，y，z}
我想得到这些数组的组合，如下所示
arr_result = {" a1x"，" a1y"，" a1z"，" a2x"，" a2y"，" a2z"，" a3x"，" a3y"，
" A3Z" ;,
" B1X"，" B1Y"，" b1z"，" B2X"，" B2Y"，" b2z"，" B3X" ，
" b3y"，" B3Z" ;,
" C1X"，" C1Y"，" C1Z"，" C2X"，" C2Y" ;，c2z，c3x，
" c3y"，" c3z"}
感谢有人可以提供示例算法帮助。
谢谢！
Hi,
I have arrays below:
arr1 = { a, b, c}
arr2 = {1, 2, 3}
arr3 = {x, y, z}
I want to get a combination of these array, as below
arr_result = { "a1x", "a1y", "a1z", "a2x", "a2y", "a2z", "a3x", "a3y",
"a3z",
"b1x", "b1y", "b1z", "b2x", "b2y", "b2z", "b3x",
"b3y", "b3z",
"c1x", "c1y", "c1z", "c2x", "c2y", "c2z", "c3x",
"c3y", "c3z"}
appreciate if someone can help with example algorithm.
Thanks!
也许：
string s [] = new string [arr1.Length * arr2.Length * arr3.Length];
for（int i = 0; i< arr1.Length; ++ i）
for（int j = 0; j< arr1.Length; ++ j）
for（int k = 0; k< arr1.Length; ++ k）
s [i + j + k] = String.Concat（s [i]，s [j]，s [k]）;
希望这会有所帮助。
Moty
Hi,
Maybe:
string s[] = new string[arr1.Length*arr2.Length*arr3.Length];
for( int i=0; i<arr1.Length; ++i )
for( int j=0; j<arr1.Length; ++j )
for( int k=0; k<arr1.Length; ++k )
s[i+j+k] = String.Concat(s[i], s[j], s[k]);
Hope this helps.
Moty
2007年6月14日星期四17:32:50 + 0800£？Moty Michaely< Mo ***** @ gmail.com>
写道：
At Thu, 14 Jun 2007 17:32:50 +0800￡?Moty Michaely <Mo*****@gmail.com>
wrote:
6月14日下午12:16，csfon ... @ gmail.com写道：
On Jun 14, 12:16 pm, csfon...@gmail.com wrote:
>
我的数组如下：
arr1 = {a，b，c}
arr2 = {1， 2,3}
arr3 = {x，y，z}
我想得到这些数组的组合，如下所示
arr_result = {" a1x，a1y，a1z，a2x，a2y，a2z，a3x， a3y" ;,
" A3Z" ;,
" B1X"，" B1Y"，" b1z"，" B2X"，" B2Y"，" b2z"，" B3X" ，
" b3y"，" B3Z" ;,
" C1X"，" C1Y"，" C1Z"，" C2X"，" C2Y"，" C2Z"，" ; c3x"，
" c3y"，" c3z"}
感谢有人可以提供示例算法的帮助。
谢谢！
>Hi,
I have arrays below:
arr1 = { a, b, c}
arr2 = {1, 2, 3}
arr3 = {x, y, z}
I want to get a combination of these array, as below
arr_result = { "a1x", "a1y", "a1z", "a2x", "a2y", "a2z", "a3x", "a3y",
"a3z",
"b1x", "b1y", "b1z", "b2x", "b2y", "b2z", "b3x",
"b3y", "b3z",
"c1x", "c1y", "c1z", "c2x", "c2y", "c2z", "c3x",
"c3y", "c3z"}
appreciate if someone can help with example algorithm.
Thanks!
也许：
string s [] = new string [arr1.Length * arr2.Length * arr3.Length];
for（int i = 0; i< arr1.Length; ++ i）
for（int j = 0; j< arr1.Length; ++ j）
for（int k = 0; k< arr1.Length; ++ k）
s [i + j + k] = String.Concat（s [i]，s [j]，s [k]）;
希望这会有所帮助。
Moty
Hi,
Maybe:
string s[] = new string[arr1.Length*arr2.Length*arr3.Length];
for( int i=0; i<arr1.Length; ++i )
for( int j=0; j<arr1.Length; ++j )
for( int k=0; k<arr1.Length; ++k )
s[i+j+k] = String.Concat(s[i], s[j], s[k]);
Hope this helps.
Moty
您的代码可能有误，尤其是s的索引。
我认为它应该是这样的：
s [i * arr2.Length * arr3.Length + j * arr3.Length + k] =
String.Concat（arr1 [i]，arr2 [j] ，arr3 [k]）;
-
最好的问候。
Maple
Your code maybe wrong, especially the index of s.
I think it should be this:
s[i * arr2.Length * arr3.Length + j * arr3.Length + k] =
String.Concat(arr1[i], arr2[j], arr3[k]);
--
Best Regards.
Maple
< cs ****** @ gmail.comwrote in message
news：11 ********** ************@x35g2000prf.googlegr oups.com ...
<cs******@gmail.comwrote in message
news:11**********************@x35g2000prf.googlegr oups.com...
我有下面的数组：
arr1 = {a，b，c}
a rr2 = {1,2,3}
arr3 = {x，y，z}
我想得到这些数组的组合，如下所示
arr_result = {" a1x"，" a1y"，" a1z"，" a2x"，" a2y"，" a2z"，" a3x"， a3y，
" a3z"，
" b1x"，" b1y"，" b1z"，" b2x"，" b2y" ，" b2z"，" B3X" ;,
" b3y"，" B3Z" ;,
" C1X"，" C1Y"，" C1Z" ;，c2x，c2y，c2z，c3x，
" c3y"，" c3z"}
$ b如果有人可以帮助使用示例算法，$ b会感激。
Hi,
I have arrays below:
arr1 = { a, b, c}
arr2 = {1, 2, 3}
arr3 = {x, y, z}
I want to get a combination of these array, as below
arr_result = { "a1x", "a1y", "a1z", "a2x", "a2y", "a2z", "a3x", "a3y",
"a3z",
"b1x", "b1y", "b1z", "b2x", "b2y", "b2z", "b3x",
"b3y", "b3z",
"c1x", "c1y", "c1z", "c2x", "c2y", "c2z", "c3x",
"c3y", "c3z"}
appreciate if someone can help with example algorithm.
三个嵌套的for loop shoud给出你想要的结果：
string [] arr_result = new string [arr1.Length + arr2.Length + arr3.Length];
int i = 0;
foreach（arr1中的字符串s1）
foreach（strr s2 in arr2）
foreach（arr3中的字符串s3）
arr_result [i ++] = s1 + s2 + s3;
Three nested "for" loops shoud give the result that you want:
string[] arr_result = new string[arr1.Length+arr2.Length+arr3.Length];
int i=0;
foreach (string s1 in arr1)
foreach (strng s2 in arr2)
foreach (string s3 in arr3)
arr_result[i++]=s1+s2+s3;
这篇关于组合数量的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
