如何解决一个功能? [英] How to solve a function?
问题描述
我有一个方法
双myfunction(双param1){
//代码在这里
}
Method接受1个参数,并返回一个double。它是连续的。
C sharp中的任何功能都可以帮助我找到param1
这样我的功能最小化了吗?
I have a method
double myfunction(double param1){
// code here
}
The Method takes 1 parameter, and returns a double. It is continuous.
Are tehre any functions in C sharp that will help me to find param1
such that myfunction is minimised?
推荐答案
2008年9月5日星期五03:47:26 -0700(PDT),Bernard.Mangay写道:
On Fri, 5 Sep 2008 03:47:26 -0700 (PDT), Bernard.Mangay wrote:
我有一个方法
double myfunction(double param1){
//这里代码
}
Method接受1个参数,并返回一个double。它是连续的。
C sharp中的任何函数都可以帮助我找到param1
这样我的函数被最小化了吗?
I have a method
double myfunction(double param1){
// code here
}
The Method takes 1 parameter, and returns a double. It is continuous.
Are tehre any functions in C sharp that will help me to find param1
such that myfunction is minimised?
我是唯一一个不明白他想要的人吗? :S
伯纳德,请你解释一下你想要完成什么?
David
-
。 '。 Debian维护者| http://wiki.debian.org/DavidPaleino
::'':Linuxer#334216 - | - http://www.hanskalabs.net /
`。 '''`GPG:1392B174 ---- | ---- http://snipr.com/ qa_page
` - 2BAB C625 4E66 E7B8 450A C3E1 E6AA 9017 1392 B174
Am I the only one who didn''t understand what he wants? :S
Bernard, would you please explain what do you want to accomplish?
David
--
. ''''`. Debian maintainer | http://wiki.debian.org/DavidPaleino
: :'' : Linuxer #334216 --|-- http://www.hanskalabs.net/
`. `''` GPG: 1392B174 ----|---- http://snipr.com/qa_page
`- 2BAB C625 4E66 E7B8 450A C3E1 E6AA 9017 1392 B174
9月5日,11: 47 * am,Bernard.Mangay < fcm ... @ googlemail.comwrote:
On Sep 5, 11:47*am, "Bernard.Mangay" <fcm...@googlemail.comwrote:
我有一个方法
double myfunction(double param1){
//这里的代码
}
方法需要1个参数,并返回一个双。 *它是连续的。
C sharp中的任何函数都可以帮助我找到param1
这样我的函数最小化了吗?
I have a method
double myfunction(double param1){
// code here
}
The Method takes 1 parameter, and returns a double. *It is continuous.
Are tehre any functions in C sharp that will help me to find param1
such that myfunction is minimised?
当然不是用C#语言,但是有一个新的MS库,
可以帮到你:
< a rel =nofollowhref =http://code.msdn.microsoft.com/solverfoundationfs1target =_ blank> http://code.msdn.microsoft.com/solverfoundationfs1
我假设你只是在寻找当地的最低价格?
非常容易提出一个连续的函数,在任何理智的时间长度内很难找到最小的
。
Jon
Certainly not in C# as a language, but there''s a new MS library which
might help you:
http://code.msdn.microsoft.com/solverfoundationfs1
I assume you''re only looking for a local minimum? It''s pretty easy to
come up with a continuous function which would be hard to find the
minimum for programmatically in any sane length of time.
Jon
9月5日,11:49 * am,David Paleino< dDOTpale ... @ gmail.co-mwrote:
On Sep 5, 11:49*am, David Paleino <dDOTpale...@gmail.c-o-mwrote:
我是唯一一个不明白他想要的人吗? :S
Am I the only one who didn''t understand what he wants? :S
可能不是,但我很确定我理解它。
Possibly not, but I''m pretty sure I understand it.
Bernard,你能解释一下你想要完成什么吗?
Bernard, would you please explain what do you want to accomplish?
考虑一个函数,如x = x *(x-1)。当x为1/2时,它具有最小值
。我相信伯纳德试图获得该源值
(1/2)给出了计算任何
源的目标值的方法。
Jon
Consider a function such as x =x*(x-1). That has a minimum value
when x is 1/2. I believe Bernard was trying to get that source value
(1/2) given the method which would compute the target value for any
source.
Jon
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