以下两个代码部分如何相同 [英] how the following two code parts same
问题描述
以下两个代码部分如何相同：
#include< stdio.h>
void main（）
{
char i = NULL;
char& q = i;
^^^^
printf（"％d"，i）;
printf（"％d"，q）;
}
O / p .................. 0 0
#include< stdio.h>
void main（）
{
char i = NULL;
char q = i;
^^
printf（"％ d"，i）;
printf（"％d"，q）;
}
O / p。 ............... 0 0
how the following two code parts same:
#include <stdio.h>
void main ()
{
char i = NULL;
char &q = i;
^^^^
printf ( "%d", i);
printf ("%d", q);
}
O/p.................. 0 0
#include <stdio.h>
void main ()
{
char i = NULL;
char q = i;
^^
printf ( "%d", i);
printf ("%d", q);
}
O/p ................ 0 0
推荐答案
12月7日下午1:00，saipathak .. 。@ gmail.com写道：
On Dec 7, 1:00 pm, saipathak...@gmail.com wrote:
以下两个代码部分如何相同：
#include< stdio.h> ;
void main（）
{
char i = NULL;
char& q = i;
^^^^
printf（"％d"，i）;
printf（"％d"，q）;
}
O / p ... ............... 0 0
#include< stdio.h>
无效main（）
{
char i = NULL;
char q = i;
^^
printf（"％d"，i）;
printf（"％d"，q ）;
}
O / p ................ 0 0
how the following two code parts same:
#include <stdio.h>
void main ()
{
char i = NULL;
char &q = i;
^^^^
printf ( "%d", i);
printf ("%d", q);
}
O/p.................. 0 0
#include <stdio.h>
void main ()
{
char i = NULL;
char q = i;
^^
printf ( "%d", i);
printf ("%d", q);
}
O/p ................ 0 0
它们是相同的除了行
They are the same except for the lines
char& q = i;
char &q = i;
和
and
char q = i;
char q = i;
-
Fred
--
Fred
12月8日凌晨2:03 ，fred.l.kleinschm ... @ boeing.com写道：
On Dec 8, 2:03 am, fred.l.kleinschm...@boeing.com wrote:
12月7日下午1:00，saipathak ... @ gmail.com写道：
On Dec 7, 1:00 pm, saipathak...@gmail.com wrote:
以下两个代码部分如何相同：
how the following two code parts same:
#include< stdio。 h取代;
#include <stdio.h>
void main（）
{
void main ()
{
char i = NULL;
char i = NULL;
char& q = i;
^^^^
char &q = i;
^^^^
printf（"％d"，i）;
printf ( "%d", i);
printf（"％d"，q）;
printf ("%d", q);
}
}
O / p ...... ............ 0 0
O/p.................. 0 0
#include< stdio.h>
#include <stdio.h>
void main（）
{
void main ()
{
char i = NULL;
char i = NULL;
char q = i;
^^
char q = i;
^^
printf（"％d"，i）;
printf ( "%d", i);
printf（"％d"，q）;
printf ("%d", q);
}
}
O / p ...... .......... 0 0
O/p ................ 0 0
它们是相同的除了行
They are the same except for the lines
char& q = i;
char &q = i;
和
and
char q = i;
char q = i;
-
Fred
--
Fred
i我问两个代码是如何显示的相同的输出。
i am asking how both code is showing same output.
sa ******* ***@gmail.com 写道：
以下两个代码部分如何相同：
＃ include< stdio.h>
void main（）
how the following two code parts same:
#include <stdio.h>
void main ()
Nope。在托管环境中，main（）按定义返回int。你的意思是
int main（无效）
这里
Nope. In a hosted environment, main() returns int by definition. You really mean
int main(void)
here
{
char i = NULL;
{
char i = NULL;
您应该看到一个诊断，指示您正在将指针转换为
整数（类型）而不进行强制转换。话虽如此，我现在应该初始化
为零。
You should see a diagnostic indicating that you are converting a pointer to an
integer (type) without a cast. Having said that, i should now be initialized
to zero.
>
char& q = i;
>
char &q = i;
语法错误。你的程序不应该编译。
Syntax error. Your program should not compile.
>
printf（"％d"，i）;
printf（"％d"，q）;
}
O / p .......... ........ 0 0
>
printf ( "%d", i);
printf ("%d", q);
}
O/p.................. 0 0
我不相信你。
I don''t believe you.
>
#include< stdio.h>
void main（）
>
#include <stdio.h>
void main ()
再次，
int main（无效）
Again,
int main(void)
{
char i = NULL;
{
char i = NULL;
您应该看到一个诊断，指示您正在将指针转换为
整数（类型）而不进行强制转换。话虽如此，我现在应该初始化
为零。
You should see a diagnostic indicating that you are converting a pointer to an
integer (type) without a cast. Having said that, i should now be initialized
to zero.
char q = i;
char q = i;
q初始化为i的内容。由于我在此声明之前初始化为零并且没有更改
，现在q也应该设置为零。
q is initialized to the contents of i. Since i is initialized to zero and not
changed before this statement, q should now also be set to zero.
>
printf（"％d"，i）;
printf（"％d"，q）;
}
O / p ................ 0 0
>
printf ( "%d", i);
printf ("%d", q);
}
O/p ................ 0 0
OK
那么，你的问题是什么？
-
Lew Pitcher
Master Code Code& JOAT-in-training |已注册的Linux用户＃112576
http://pitcher.digitalfreehold.ca/ |可根据要求提供GPG公钥
---------- Slackware - 因为我知道我在做什么。 ------
OK
So, what''s your problem?
--
Lew Pitcher
Master Codewright & JOAT-in-training | Registered Linux User #112576
http://pitcher.digitalfreehold.ca/ | GPG public key available by request
---------- Slackware - Because I know what I''m doing. ------
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