比较C ++中的字符串 [英] Compare string in C++

问题描述

#include< iostream>

#include< string>

int main（void）{


using namespace std;

string STR =（" TEST"）;

const std :: string :: size_type STR_SIZE = STR.size（）;


int count = 0;

while（count< = STR_SIZE）{

if（STR [count] =（''E''' ））{* / b $ b cout<<"'FOUND letter E at"<<<" "<< count<< endl;

}


count ++;

}

返回1; < br $>
}

输出：

FOUND字母E at 0

FOUND字母E at 1

FOUND字母E在2

FOUND字母E在3

FOUND字母E在4


有些问题与 ; if（STR [count] =（''E''）"


我希望输出为：

FOUND letter at 1


请给我一些提示。

谢谢，

#include <iostream>
#include <string>
int main (void){

using namespace std;
string STR =("TEST");
const std::string::size_type STR_SIZE = STR.size();

int count =0;
while ( count <= STR_SIZE){
if (STR[count]= (''E'')){
cout <<"FOUND letter E at"<<" "<< count<<endl;
}

count++;
}
return 1;
}
output:
FOUND letter E at 0
FOUND letter E at 1
FOUND letter E at 2
FOUND letter E at 3
FOUND letter E at 4

Some thing wrong with "if (STR[count]= (''E'')"

I would like to have the output as:
FOUND letter at 1

Please give me some hints .
Thanks,

推荐答案

tv****@hotmail.com 写道：

#include< iostream>
#include< string>
int main（void）{

使用命名空间std;
字符串STR =（" TEST"）;
const std :: string :: size_type STR_SIZE = STR.size（）;

int count = 0;
while（count< = STR_SIZE）{
if（STR [ count] =（''E''））{
co ut<<<<" FOUND letter E at"<<<" "<< count<< endl;
}
数++;
}
返回1;
}
输出：
FOUND字母E在0
找到字母E在1
找到字母E在2
找到字母E在3
找到字母E在4

有些不对劲用if（STR [count] =（''E''）"

我希望输出为：
FOUND letter at 1

请给我一些提示。
谢谢，

#include <iostream>
#include <string>
int main (void){

using namespace std;
string STR =("TEST");
const std::string::size_type STR_SIZE = STR.size();

int count =0;
while ( count <= STR_SIZE){
if (STR[count]= (''E'')){
cout <<"FOUND letter E at"<<" "<< count<<endl;
}

count++;
}
return 1;
}
output:
FOUND letter E at 0
FOUND letter E at 1
FOUND letter E at 2
FOUND letter E at 3
FOUND letter E at 4

Some thing wrong with "if (STR[count]= (''E'')"

I would like to have the output as:
FOUND letter at 1

Please give me some hints .
Thanks,

=是赋值运算符。

==是测试平等运营商。


-

Scott McPhillips [VC ++ MVP]

= is the assignment operator.
== is the test for equality operator.

--
Scott McPhillips [VC++ MVP]

tvn ... @ hotmail.com写道：

[e-mail] wrote:

#include< iostream>
#include< string>
int main（void）{

using namespace std;
string STR =（" TEST"）;
const std :: string :: size_type STR_SIZE = STR.size（）;

int count = 0;
while（count< = STR_SIZE）{
if（STR [count] =（ E））{


当心，=不是==。第一个分配，第二个分配。


if（STR [count] ==（''E''））

cout<< ;FOUND letter E at<<<" "<< count<< endl;
}

count ++;
}
返回1;
}

#include <iostream>
#include <string>
int main (void){

using namespace std;
string STR =("TEST");
const std::string::size_type STR_SIZE = STR.size();

int count =0;
while ( count <= STR_SIZE){
if (STR[count]= (''E'')){
Watch out, = is not ==. The first one assigns, the second one compares.

if (STR[count] == (''E''))
cout <<"FOUND letter E at"<<" "<< count<<endl;
}

count++;
}
return 1;
}

1）下次格式化代码。

2）大写字母应保留给宏

3）main（）应返回0，EXIT_SUCCESS或EXIT_FAILURE

Jonathan

1) Format your code next time.
2) Uppercase names should be reserved to macros
3) main() should return either 0, EXIT_SUCCESS or EXIT_FAILURE
Jonathan

Jonathan Mcdougall写道：

Jonathan Mcdougall wrote:

tvn。 .. @ hotmail.com写道：

[e-mail] wrote:

#include< iostream>
#include< string>
int main（void）{

using namespace std;
string STR =（" TEST"）;
const std :: string :: size_type STR_SIZE = STR.size（）;

int count = 0 ;
while（count< = STR_SIZE）{

#include <iostream>
#include <string>
int main (void){

using namespace std;
string STR =("TEST");
const std::string::size_type STR_SIZE = STR.size();

int count =0;
while ( count <= STR_SIZE){

顺便说一句，这是无效的，你会读一个过去的最后一个

字符。制作


while（count< STR_SIZE）

Jonathan

And by the way, this is invalid, you''ll read one past the last
character. Make it

while (count < STR_SIZE)
Jonathan

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