Guid应包含32位数字和4个破折号（xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx）。错误？ [英] Guid should contain 32 digits with 4 dashes (xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx). error?

问题描述

我需要将这六个字段保存在同一列中，但不能保存在同一行和同一个单元格中。每个字段都有默认GUID。所以我决定将默认guid放在一个列表中，并将字段放在一个列表中，然后调用该特定列表中我们想要的对象。

I need to save those six fields in same column but not in same row and same cell. each field have default GUID.so i decided to put that default guid's in one list and fields in one list and call that object of that particular list where we want .

ArrayList Alist = new ArrayList();
        {
            Alist.Add("FD713788-B5AE-49FF-8B2C-F311B9CB0CC4");
            Alist.Add("64B512E7-46AE-4989-A049-A446118099C4");
            Alist.Add("376D45C8-659D-4ACE-B249-CFBF4F231915");
            Alist.Add("59A2449A-C5C6-45B5-AA00-F535D83AD48B");
            Alist.Add("03ADA903-D09A-4F53-8B67-7347A08EDAB1");
            Alist.Add("2F405521-06A0-427C-B9A3-56B8931CFC57");
        }

        ArrayList objValue = new ArrayList();
        {
            objValue.Add(viewmodel.TinNo);
            objValue.Add(viewmodel.CstNo);
            objValue.Add(viewmodel.PanNo);
            objValue.Add(viewmodel.CinNo);
            objValue.Add(viewmodel.ExciseRegNo);
            objValue.Add(viewmodel.ServiceTaxNo);
        }

   var TaxInfoTaxFiledclassobj = new TaxInfoTaxFiled()
        {

            TaxInfoTaxFieldID = TaxInfoTaxFieldObj,
            TaxFieldID = new Guid(Alist .ToString ()),
            FieldValue = objValue.ToString(),
        };

所有工作正常但在TaxFieldID它显示从列表计算的计数，但保存时显示Guid应包含32位数字，包含4个破折号（xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx）。错误？在TaxFieldID我该怎么做才能解决这个问题

All are working Fine but in TaxFieldID it show the count which has been calculated from list but while saving it shows Guid should contain 32 digits with 4 dashes (xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx). error? in TaxFieldID what shall i do to resolve this probelm

推荐答案

您正在尝试将 ArrayList 转换为 Guid 。

You are trying to convert the ArrayList to Guid.

TaxFieldID = new Guid(Alist .ToString ())

使用迭代器（对于/ while / foreach）迭代 ArrayList 项并转换每个项目。

在第一眼看，下面的行可能会抛出错误：

On the first look, below line may throw an error:

TaxFieldID = new Guid(Alist .ToString ()),

Guid构造函数不接受字符串数组，它接受单个字符串。

Guid constructor does not accept array of strings, it accepts single string.

Guid g = new Guid(Alist[0]);

请参阅：指导构造函数（系统） [ ^ ]

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