在C ++中对给定函数进行完整性检查 [英] Sanity check of the given function in C++

问题描述

大家好，

我在接受采访时被问到以下问题，并被问及是否有健全检查问题。任何人都可以帮助我：



//以下函数应该增加x的值

Hi All,
I was asked following question in an interview and was asked that it is having sanity check issues. Could anyone please help me in this:

//following function should increment the value of x

void increment(int x)
{
    x++;
    return; 
}

问候



我是什么尝试过：



我已经要求按值更改副本以通过引用传递它仍然给出错误。

Regards

What I have tried:

I have asked to change copy by value to pass by reference by it was still giving error.

推荐答案

此代码不应该给出错误。如果通过引用传递，则x将在调用代码中递增。如果你更改了它并得到了错误，请给我们新的代码和错误如果你被卡住了

This code should not give an error. If you pass by reference, then x will be incremented in the calling code. If you changed it and got an error, give us the new code and the error if you're stuck

这个函数中的一个问题可能是它有没有外部效应。输入x在堆栈上创建，在本地修改并被销毁。



因此该函数仅修改本地x，仅此而已。您可以使用& -operator更改此行为，如前所述。

One issue in this function can be that it has NO EXTERNAL EFFECTS. The input x is created on the stack, locally modified and than destroyed.

So the function only modies the local x and nothing more. You can change this behaviour with the &-operator, as mentioned before.

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