谁能在第47行发现错误 [英] Can anyone spot the error here on line 47

问题描述

我正在进行更新，并且在我的更新脚本中第47行遇到障碍，有一个错误，但无法发现它，一直在寻找它



也许第三只眼睛会看到我不能的，任何帮助都会非常感激。



我尝试了什么： < br $> b $ b

I am doing an update and i keep hitting a snag on line 47 in my update script, there is an error there but cannot spot it, been looking for it whole day

maybe a third eye will see what i cannot, any help will be much appreciated.

What I have tried:

<pre><?php		
		
		
		if(isset($_POST['edit']))
		{
		//Capture values from form and store in php variables
		 $title=$_POST['title'];
		 $fname=$_POST['fname'];
		 $address=$_POST['address']; 
		 $sex=$_POST['gender'];
		 $hobbies=join(" ,", $_POST['hobby']);
		 $uname=$_POST['uname'];
		 $pword=$_POST['currentpword'];
		 
		 include'db_config.php';
		 
		 
		$sql = "SELECT uname,pword FROM member WHERE uname='$uname' AND pword=md5('$pword')";
		
		if($result=mysqli_query($con,$sql))
		{
			$rowcount=mysqli_num_rows($result);
		
			if($rowcount==1)
			{
				$sql="UPDATE member 
				SET title='$title', name='$fname', address='$address', sex='$sex', hobby='$hobby', uname='$uname',
				WHERE pword=md5('$pword')";
			
				if(mysqli_query($con,$sql))
				{
					mysqli_close($con);
					
					echo "<script type=\"text/javascript\">
						  alert('your information has been updated $title $name');
						  window.location\view.php\";
						  </script>";
				}
				
				else
				{
					echo"<script type\"text/javascript\">
						alert('error');
						window.location/edit.php\";
						</script>";
				}
				else<--- the arrow point to where the error is. 
				{
					echo mysqli_error($con);
				}
			}
			
		}
		
		
		
?>

推荐答案

_POST [' edit']））
{
// 从中捕获值在php变量中形成和存储

_POST['edit'])) { //Capture values from form and store in php variables

title =

_POST [' title'];

_POST['title'];

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