如果我有一个指向结构的指针，该结构具有指向结构的数组？如何访问特定的数组元素？ [英] How do I access a specific array element if I have a pointer to a struct which has a pointer to and a array of structs?

问题描述

如果我有一个指向结构的指针，如何指向一个结构数组的指针，我如何访问特定的数组元素？





struct node {

int number;

};



struct queue {

struct node * array;

};



int main（）{

struct queue *队列;

struct node * t;

queues =（struct red *）malloc（sizeof（struct queue））;

queues- > array =（struct node *）malloc（10 * sizeof（struct node））;

queues-> array-> number = 5;

queues- >（数组+ 1） - >数字= 6

}



我的尝试：



queues-> array-> number可以访问第一个元素，但是如何访问其他元素？



queues->（array + i） - >数字不起作用和

queues-> array [i] - >数字不起作用

解决方案

您需要使用点引用器，因为 array [i] 是一个正确的引用，而不是一个指针（我知道它很混乱，但这是C中的规则）。所以你应该按如下方式编写代码：

  int  i =  3 ;  //  或任何其他偏移量 
 queues-> array [i] .number = < span class =code-digit> 6 ; 

首先，让它编译！ red未声明：

 queues =（struct red *）malloc（sizeof（struct queue））; 

我假设你的意思是：

 queues =（struct queue *）malloc（sizeof（struct queue））; 

然后只需将它用作数组：

 queues-> array [1] .number = 6; 
 struct node * n = queues-> array; 
 for（int i = 0; i< 10; i ++）
 {
 printf（％u \ nn，n [i]）; 
} 

会给你：

 5 
 6 
 0 
 0 
 0 
 0 
 0 
 0 
 0 
 0 

（尽管零可能会被随机数据替换，具体取决于您的编译器）

How do I access a specific array element if I have a pointer to a struct which has a pointer to an array of structs?


struct node {
int number;
};

struct queue {
struct node *array;
};

int main() {
struct queue *queues;
struct node *t;
queues = (struct red*)malloc(sizeof(struct queue));
queues->array = (struct node*)malloc(10 * sizeof(struct node));
queues->array->number = 5;
queues->(array + 1)->number = 6
}

What I have tried:

queues->array->number can access the first element,but how do i access other elements?

queues->(array + i)->number doesnt work and
queues->array[i]->number doesnt work

解决方案

You need to use the dot referencer since array[i] is a proper reference, rather than a pointer (I know it's confusing but that is the rule in C). So you should code it as follows:

int i = 3; // or any other offset
queues->array[i].number = 6;

First off, get it to compile! "red" is not declared:

queues = (struct red*)malloc(sizeof(struct queue));

I assume you meant:

queues = (struct queue*)malloc(sizeof(struct queue));

Then just use it as an array:

queues->array[1].number = 6;
struct node *n = queues->array;
for (int i = 0; i < 10; i++)
    {
    printf("%u\n", n[i]);
    }

Will give you:

5
6
0
0
0
0
0
0
0
0

(Though the zeros may be replaced with random data, depending on your compiler)

这篇关于如果我有一个指向结构的指针，该结构具有指向结构的数组？如何访问特定的数组元素？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！