为什么我的代码有时会给出不同的结果 [英] Why do my code gives different result at times

问题描述

我正在试图找出为什么我的代码给了我不同的结果是运行时



例如在第一次测试时工作

第二次测试完全不同的结果

第三次测试没有任何结果



以下是我的代码：



char * Amy [] = {Olivia \\\
Emma \\\
Ava \\\
Mia \\\
Charloth \ nn Noah \ Liam \ Ben \ n Oliver \\ \\ n将};



printf（\ n Amy's Profile \ n）;







printf（学生姓名：\ n％s，* Amy，\ n）;



我尝试了什么：



我没有尝试过多，因为我看不太清楚我的错误

解决方案

您将不得不更准确地解决问题发生时使用的代码：如果我将代码粘贴到在线编译器中并尝试它：

  #include   <   stdio.h  >  
  
  int  main（）
 {
 printf（  Hello World \ n）; 
  char  * Amy [] = {  Olivia \\\
 Emma \\\
 Ava \\\
 Mia \\\
 Charloth \ nn Noah \ Liam \ Ben \ n Oliver \ n will}; 
 printf（  \ n Amy的个人资料\ n）; 
 printf（ 学生姓名：\ n％s，* Amy，  \ n）; 
  return   0 ; 
} 

每次运行它都会做同样的事情：

 Hello World 
 
 Amy's个人资料
学生姓名：
 Olivia 
 Emma 
 Ava 
 Mia 
 Charloth 
 Noah 
 Liam 
 Ben 
 Oliver 
将

这是我的期望。

我建议对你的代码进行一次改进：

< pre lang =c ++> printf（ 学生姓名：\ n％s，Amy [ 0 ]， \ n ）;

通常是比使用指针更好的访问数组的方法。它对你的代码输出没有任何影响。

引用：

char * Amy [ ] = {Olivia \\\
Emma \\\
Ava \\\
Mia \\\
Charloth \ nn Noah \ Liam \ Ben \ n Oliver \ n will will}};

以上line定义了一个只有一个项目的指针数组（字符）。

虽然技术上不是一个错误，但它可能不是你想要的。

Quote：

printf（学生姓名：\ n％s，* Amy，\ n）;

以上行不正确（请参阅 printf文档 [ ^ ]）：您的格式字符串只指定一个参数（％s ），但你提供两个（ amy [0] 和\ n） 。一个不错的编译器会产生警告。



我会这样写的：

  #include   <   stdio.h  >  
  
  int  main（）
 {
  const   char  * Amy =   Olivia \ n Emma \\\
 Ava \\\
 Mia \\\
 Charloth \ Noah \ Liam \ Ben \\ n奥利弗\ n将; 
 printf（  \ n Amy的个人资料\ n）; 
 printf（ 学生姓名：\ n％s \ n，Amy） ; 
  return   0 ; 
} 

I'm trying to figure out why does my code gives me different results are runtime

for instance on first test it works
second test a totally different result
third test no result at all

below is my code :

char *Amy[] = {"Olivia \n Emma \n Ava\n Mia\n Charloth\n Noah \n Liam \n Ben \n Oliver \n will"};

printf("\n Amy's Profile\n");



printf("Student Names :\n %s",*Amy,"\n");

What I have tried:

I haven't try much at all since I don't quite see my mistake

解决方案

You're going to have to be more exact about the code you use when the problem occurs: If I paste your code into an online compiler and try it:

#include <stdio.h>

int main()
    {
    printf("Hello World\n");
    char *Amy[] = {"Olivia \n Emma \n Ava\n Mia\n Charloth\n Noah \n Liam \n Ben \n Oliver \n will"};
    printf("\n Amy's Profile\n");
    printf("Student Names :\n %s",*Amy,"\n");
    return 0;
    }

It does the same thing each time I run it:

Hello World                                                                                                                                                    
                                                                                                                                                               
 Amy's Profile                                                                                                                                                 
Student Names :                                                                                                                                                
 Olivia                                                                                                                                                        
 Emma                                                                                                                                                          
 Ava                                                                                                                                                           
 Mia                                                                                                                                                           
 Charloth                                                                                                                                                      
 Noah                                                                                                                                                          
 Liam                                                                                                                                                          
 Ben                                                                                                                                                           
 Oliver                                                                                                                                                        
 will

Which is what I expect.
I would suggest one improvement to your code though:

printf("Student Names :\n %s", Amy[0], "\n");

Is normally a better way of accessing an array than using a pointer. It won't make any difference to your code output though.

Quote:

char *Amy[] = {"Olivia \n Emma \n Ava\n Mia\n Charloth\n Noah \n Liam \n Ben \n Oliver \n will"};

The above line defines an array of pointers (to characters) having just one item.
While not technically a mistake, it is probably not what you intended.

Quote:

printf("Student Names :\n %s",*Amy,"\n");

The above line is incorrect (see the printf documentation[^]): your format string specifies just one argument (%s), but you are providing two (amy[0] and "\n"). A decent compiler would produce a warning.

I would have written it this way:

#include <stdio.h>

int main()
{
  const char *Amy = "Olivia \n Emma \n Ava\n Mia\n Charloth\n Noah \n Liam \n Ben \n Oliver \n will";
  printf("\n Amy's Profile\n");
  printf("Student Names :\n %s\n", Amy);
  return 0;
}

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