如何使用参数将路径文件作为输入数据提供给PowerShell中的其他脚本？ [英] How to use argument to get path file as an input data to other script in powershell?

问题描述

 0 
 
 
我想读取2个文本文件（Byte2.txt和FB.txt），但我不想把路径放在脚本，我想在从命令行运行脚本到解析脚本路径时使用参数。我的命令，当我从命令行运行脚本时：
 
 $ PowerShell.exe Script.ps1 arg1 arg2 
 
 arg1表示Byte.txt的路径，arg2表示路径FB.txt 
 
 我尝试过： 
 
< pre> 
 $ file = $ Args [0] 
 $ Data = $ Args [1] 
 $ file_2 = Get-Content
 $ file_2 
 $ Data_2 = Get -content
 $ Data_2 

我从cmd执行该脚本：

 $ PS.exe Script.ps1 C：\ User \ Pyt.txt C：\ User \ NF.txt 

解决方案

PowerShell.exe Script.ps1 arg1 arg2

arg1表示Byte.txt的路径，arg2表示FB.txt的路径

我尝试过：

< pre>

file =

Args [0]

0


I want to read a 2 of text file (Byte2.txt and FB.txt), but I dont want to put the path on the script, I want to use argument when I run the script from command line to parsing the path to my script. My expextation, when I run the script from command line :

$PowerShell.exe Script.ps1 arg1 arg2

arg1 represent the path of Byte.txt and arg2 represent the path of FB.txt

What I have tried:

<pre>
$file = $Args[0]
$Data = $Args [1]
$file_2 = Get-Content " "
$file_2
$Data_2 = Get-content " "
$Data_2

I execute that script from cmd :

$PS.exe Script.ps1 C:\User\Byte.txt C:\User\FB.txt

解决方案

PowerShell.exe Script.ps1 arg1 arg2 arg1 represent the path of Byte.txt and arg2 represent the path of FB.txt What I have tried: <pre>

file =

Args[0]

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