为什么他们的a =“0”？在方法声明的最后？ [英] Why is their a "=0" at the end of the method declaration?

问题描述

为什么在方法声明结束时他们的= 0？



class GamePiece {public：virtual std :: unique_ptr< gamepiece> clone（）const = 0; };



我尝试了什么：



为什么他们是方法声明结束时= 0？



类GamePiece {public：virtual std :: unique_ptr< gamepiece> clone（）const = 0; };

why is their a "=0" at the end of the method declaration?

class GamePiece { public: virtual std::unique_ptr<gamepiece> clone() const= 0; };

What I have tried:

why is their a "=0" at the end of the method declaration?

class GamePiece { public: virtual std::unique_ptr<gamepiece> clone() const= 0; };

推荐答案

这是一个纯虚函数。如果一个类至少有一个纯虚函数，则它是抽象的。通过在声明中赋值0来声明纯虚函数。阅读更多 C ++中的纯虚函数和抽象类 [ ^ ]

It is a pure virtual function. A class is abstract if it has at least one pure virtual function. A pure virtual function is declared by assigning 0 in declaration. Read more Pure Virtual Functions and Abstract Classes in C++[^]

我昨天告诉你答案，并建议（再次）你不要浪费时间在这里发布问题并实际学习C ++语言。

I told you the answer yesterday, and suggested (yet again) that you stop wasting your time posting questions here and actually studied the C++ language.

这篇关于为什么他们的a =“0”？在方法声明的最后？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！