无法解决代码挑战。 [英] Not able to solve a code challenge.

问题描述

我仍在学习编码，而我正在解决挑战。然后我遇到了这个挑战，以了解数据类型。这是一个基本的但我感到惭愧的是，即使在编码了几个月之后我也无法解决它。



挑战要求声明3个变量：一个整数，一个双和一个字符串。我们提供了3个变量，我们必须添加声明的变量，这些变量将通过输入来初始化。我们必须在屏幕上打印它们。



这是我的代码：

I am still learning to code and I was solving challenges. Then I came across this challenge to get to know about data types. It's a basic one but I feel ashamed that I am not able to solve it even after coding for months.

The challenge asks to declare 3 variables: one integer, one double and a string. We are provided with 3 variables which we have to add the declared variables which will be initialized by taking input. And we have to print them on the screen.

This is my code:

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
    int i = 4;
    double d = 4.0;
    char s[] = "HackerRank ";

    int number;
    double decimal;
    char name[50];

    scanf("%d",&number);
    scanf("%lf",&decimal);
    scanf("%*[\n] %[^\n]",name);
 	
 	printf("\n%d\n%.01lf\n%s%s\n",number+i,decimal+d,s,name);

    return 0;
}

我得到了相同的输出，但系统不接受它。然后我找到了提供解决方案的社论



这是提供的解决方案：

I am getting the same output as required but the system is not accepting it. Then I found the editorial which gave the solution

This is the solution provided :

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
    int i = 4;
    double d = 4.0;
    char s[] = "HackerRank ";

int i2;
double d2;
char s2[100]; // this is not scalable for input of unknown size

// Read inputs from stdin
scanf("%d", &i2);
scanf("%lf", &d2);
scanf("%*[\n] %[^\n]", s2); 

// Print outputs to stdout
printf("%d\n", i + i2);
printf("%.01lf\n", d + d2);
printf("%s%s", s, s2);

    return 0;
}

如果有人告诉我scanf中％* [\ n]的目的，我将不胜感激。 />


我尝试了什么：



我试图将它们并置但是我已经开始了没有发现任何差异。我首先将十进制变量声明为浮点数。后来我把它改成了两倍，但问题仍然存在。

I would appreciate if anyone tells me the purpose of %*[\n] in scanf.

What I have tried:

I tried to juxtapose them but I couln't find any disparity. I had first declared the decimal variable as a float. Later I changed it to double but the problem remains.

推荐答案

引用：

如果有人告诉我scanf中％* [\ n]的目的，我将不胜感激。

I would appreciate if anyone tells me the purpose of %*[\n] in scanf.

见这里： C库函数 - scanf（） [ ^ ]它说：

See here: C library function - scanf()[^] it says:

Quote：

*



这是一个可选的起始星号表示数据将从流中读取但被忽略，即它不存储在相应的参数中。

*

This is an optional starting asterisk indicates that the data is to be read from the stream but ignored, i.e. it is not stored in the corresponding argument.

并且两段代码的输出会略有不同：你的开始和结束都是换行，解决方案没有。将其添加到不同的输入内存大小：

And the output from the two pieces of code will be slightly different: yours starts and ends with a newline, the solution doesn't. Add that to the different input memory size:

char name[50];

char s2[100];

他们可能足以让你失败。

And they may be enough to give you a fail.

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