循环，同时增加2倍 [英] Looping while increasing by 2x

问题描述

使用c＃和visual studio处理作业。我希望用户输入他们工作的天数以及每天在列表框中显示的工资。但是，薪水需要每天翻倍。因此，第1天他们得到1便士，第2天他们得到2便士，第3天，他们得到4便士等。难以增加2倍，同时仍然保持计数仅上升一天。



我尝试过：



//声明变量

double dblDays;

double dblPay;

int intCounter = 1;







if（Double.TryParse（txtDays.Text，out dblDays））

{

for（intCounter = 1; intCounter< ; = dblDays; intCounter ++）

{

dblPay =（dblDays * .01）* intCounter;

lstDays.Items.Add（ 支付日+ intCounter.ToString（）+=+ dblPay.ToString（c））;

lblTotalPayEarnedTotal.Text = dblPay.ToString（c）;

Working on an assignment using c# and visual studio. I want the user to type in how many days they worked and the pay for each day to show in a listbox. However, the pay needs to double each day. So day 1 they get 1 penny, day 2 they get 2 pennies, day 3, they get 4 pennies, etc. Having trouble getting to increase by 2x, while still keeping the count only going up by one day.

What I have tried:

//declare the variables
double dblDays;
double dblPay;
int intCounter=1;



if (Double.TryParse(txtDays.Text, out dblDays))
{
for (intCounter = 1; intCounter <= dblDays; intCounter ++)
{
dblPay = (dblDays*.01) * intCounter;
lstDays.Items.Add("Pay for Day" + intCounter.ToString() + "=" + dblPay.ToString("c"));
lblTotalPayEarnedTotal.Text = dblPay.ToString("c");

推荐答案

更改

dblPay =（dblDays * .01）* intCounter;

to

dblPay =（dblDays * .01）* Math.Pow（2，（ intCounter-1））;



因为在数学中，

2 ^ 0 = 1

2 ^ 1 = 2

2 ^ 2 = 4

2 ^ 3 = 8

等......

change
dblPay = (dblDays*.01) * intCounter;
to
dblPay = (dblDays*.01) * Math.Pow(2,(intCounter-1));

because in math,
2^0 = 1
2^1 = 2
2^2 = 4
2^3 = 8
etc...

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