如何反转日期数组 [英] How do I reverse a date array
本文介绍了如何反转日期数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我的日期数组如下:
I have the date array as follows:
["09/23/2019", "08/23/2019", "07/23/2019", "06/23/2019", "05/23/2019", "04/23/2019", "03/23/2019", "02/23/2019", "01/23/2019", "12/23/2018"]
我需要撤销它并从18/23/2018开始。
我试过
I need to reverse it and start from 12/23/2018 instead.
I tried
dates.reverse
但它完全弄乱了格式并打印未分类的日期。还尝试了
but it completely messes up the format and print unsorted date. Also tried
dates.sort()
并对日期从01/2019到09/2019进行排序,并在最后打印12/2018。
我的尝试:
and it sorts the dates from 01/2019 to 09/2019 and prints 12/2018 at the very end.
What I have tried:
stDate = 11/20/2018
etDate = 09/19/2019
var Endnow = etDate.clone();
var Endday = etDate.date();
while(Endnow.isAfter(stDate)) {
var month = Endnow.clone().endOf("month");
if (Endnow.date() < Endday && Endday <= month.date()) {
Endnow.date(Endday);
}
dates.push(Endnow.format("MM/DD/YYYY"));
dates.reverse();
dates.sort();
Endnow = Endnow.clone().subtract({"months": 1});
}
推荐答案
function datecomp( d1, d2 )
{
var a1 = d1.split("/");
var a2 = d2.split("/");
a1 = a1[2] + a1[0] + a1[1];
a2 = a2[2] + a2[0] + a2[1];
return (parseInt(a1) - parseInt(a2));
}
dates.sort(datecomp);
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