如何在C＃中创建以下XML文件 [英] How to create following XML file in C#

问题描述

<env:Envelope xmlns:env="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ns1="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" xmlns:ns2="http://gl.ws.apps.oracle.xxdof/">
   <env:header>
      <ns1:security>
         <ns1:usernametoken>
            <ns1:username>XXXX
            <ns1:password>YYYYYYY
         
      
   
   <env:body>
      <ns2:getgldetails>
         <arg0>
            <p_from_date>01-01-2018

            <p_group_id>
             <p_je_category>Payments

            <p_je_source>SOURCE
            <p_ledger_name>OU
            <p_to_date>31-12-2018

我想在C＃中创建xml文件，与上面的xml格式相同。将从DB中提取正文部分并将其映射到相应的标记。请帮我解决这个问题



我尝试了什么：



我尝试使用Xml序列化使用下面的代码将数据转换为XML。但是输出是不同的。

I want to create xml file in C# as same as above xml format. Body section will be extracted from DB and mapped it to respective tags. kindly help me to solve this issue

What I have tried:

I tried by using Xml serialization using below code to convert the data to XML. But the output is in different.

var serxml = new System.Xml.Serialization.XmlSerializer(GLGetrequest.arg0.GetType());
                var ms = new MemoryStream();
                serxml.Serialize(ms, GLGetrequest.arg0);
                string xml = Encoding.UTF8.GetString(ms.ToArray());
                XmlDocument Add_XMLDoc = new XmlDocument();
                XmlNode Add_XMLDoc_Node = null;
                Add_XMLDoc.LoadXml(xml);

推荐答案

<?xml version="1.0"?>

-<getGLDetailsInp xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">

<p_FROM_DATE>01-01-2018</p_FROM_DATE>

<p_GROUP_ID/>

<p_JE_CATEGORY>Payments</p_JE_CATEGORY>

<p_JE_SOURCE>SOURCE</p_JE_SOURCE>

<p_LEDGER_NAME>OU</p_LEDGER_NAME>

<p_TO_DATE>31-12-2018</p_TO_DATE>

</getGLDetailsInp>

我没有得到提供的xml输出。不知道如何添加标题和精确的xmlns节点...

I'm not getting output as an provided xml. Dont know how to add headers and exact xmlns node given...

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