警告:mysql_num_rows()要求参数1为资源,布尔值在第44行的C:\ xampp \\\ ttococs \ techayotomi \register \ index.php中给出 [英] Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\techayotomi\register\index.php on line 44
问题描述
if(isset($ _ POST ['submit'])){
$ uname = $ _ POST ['username'];
$ password = $ _ POST ['password'];
$ sql =select * from regform where u_user ='。$ uname。'AND u_password ='。$ password。'限制1;
$ result = mysql_query($ sql);
if(mysql_num_rows($ result)){
header(location:loginform / home.php);
echo您已成功登录 ;
退出();
}
else {
echo您输入了错误的密码;
退出();
}
}
?>
我尝试了什么:
i试过if(mysql_num_rows($ result)== 1){
我也试过if(mysql_num_rows($ result)!= 1){
_POST ['submit'])){
uname =
_POST ['username'];
if(isset($_POST['submit'])){
$uname=$_POST['username'];
$password=$_POST['password'];
$sql="select * from regform where u_user='".$uname."'AND u_password='".$password."' limit 1";
$result=mysql_query($sql);
if(mysql_num_rows($result)){
header("location:loginform/home.php");
echo " You Have Successfully Logged in";
exit();
}
else{
echo " You Have Entered Incorrect Password";
exit();
}
}
?>
What I have tried:
i have tried if(mysql_num_rows($result)==1){
and also i have tried if(mysql_num_rows($result)!=1){解决方案_POST['submit'])){
uname=
_POST['username'];
这篇关于警告:mysql_num_rows()要求参数1为资源,布尔值在第44行的C:\ xampp \\\ ttococs \ techayotomi \register \ index.php中给出的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!